Finding a disabled field with Capybara

Question

I have a select box, with a label:

<label for="slide_orientation">Slide orientation</label>
<select disabled="" class="property" id="slide_orientation" name="slide_orientation">
  <option value="horizontal">Horizontal</option>
  <option value="vertical" selected="selected">Vertical</option>
</select>

As you can see the select box is disabled. When I try to find it with field_labeled("Slide orientation"), it returns an error:

Capybara::ElementNotFound: Unable to find field "Slide orientation"
from /Users/pascal/.rvm/gems/ruby-1.9.3-p392/gems/capybara-2.0.2/lib/capybara/result.rb:22:in `find!'

When the select box is not disabled, field_labeled("Slide orientation") returns the select element just fine.

Is this expected behavior? And if so, how would I go about finding a disabled element? In my case I need it to test if it's disabled or not.

The situation is the same for buttons: http://stackoverflow.com/questions/12917227/how-do-i-write-a-capybara-assertion-that-checks-for-the-presence-of-a-button-and — Ciro Santilli OurBigBook.com, Oct 15 '14 at 15:22

score 38 · Answer 1 · answered Sep 03 '13 at 01:42

38

Capybara 2.1.0 supports disabled filter. You can easily find disabled fields with it.

field_labeled("Slide orientation", disabled: true)

You need to specify it explicitly because the disabled filter is off by default.

answered Sep 03 '13 at 01:42

Shuhei Kagawa

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score 11 · Answer 2 · edited May 23 '17 at 12:02

11

This one passes if it has the disabled attribute.

Run with js: true and page.evaluate_script.

it "check slider orientation", js: true do
    disabled = page.evaluate_script("$('#slide_orientation').attr('disabled');")
    disabled.should == 'disabled' 
end

Update

or you can use have_css

page.should have_css("#slide_orientation[disabled]")

(stolen form this excellent answer )

edited May 23 '17 at 12:02

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answered Mar 13 '13 at 23:22

Andreas Lyngstad

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`expect(find("slide_orientation")).to be_disabled` – antiqe Feb 27 '20 at 13:45

score 8 · Answer 3 · answered Jul 20 '18 at 13:55

Since the answers to this are old and things have moved on a little since then here is an UPDATE.

If you just want to check if a field is disabled you can now do:

expect(page).to have_field 'Slide orientation', disabled: true

As per this PR: https://github.com/teamcapybara/capybara/issues/982

score 3 · Accepted Answer · edited May 23 '17 at 12:17

3

Andreas and this answer put me on the track to the final solution. Finding a disabled field with a certain label (instead of HTML id) can be achieved this way:

label_field = all("label").detect { |l| (l.text =~ /#{label}/i).present? }
raise Exception.new("Couldn't find field '#{label}'") if label_field.nil?
the_actual_field = first("##{label_field[:for]}")

Checking if that field is disabled can be done with one statement:

page.should have_css("##{label_field[:for]}[disabled]")

It still feels like a workaround instead of the best Capybara-like solution, but it works!

edited May 23 '17 at 12:17

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answered Mar 14 '13 at 15:14

Pascal Lindelauf

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ouch, unfortunately only works for structures. I usually wrap labels around the radio buttons, so I will have to figure out something else – Jesper Rønn-Jensen Aug 28 '13 at 12:32

Finding a disabled field with Capybara

4 Answers4