list of ints transform to array of integers

Question

I'm getting integeres to my controller as 123456 in one variable.

Now I want to transform each number to separated from other with comma between as array of numbers as { 1, 2, 3, 4, 5 }.

it's not duplicate cause I'm getting parameter as int instead of string. — user1765862, Mar 17 '13 at 18:37
Your title suggests you want to convert `List` to `int[]`. Can you please rephrase your question to clearly state **exactly** what you have and what you want? — Sam Harwell, Mar 17 '13 at 18:38
`123456.ToString().Select(c => (int) Char.GetNumericValue(c))` (from linked answer) — Corak, Mar 17 '13 at 18:45

ryan · Accepted Answer · 2013-03-17T19:03:56.057

1

Try this

var integers = "123456";
var enumOfInts = integers.ToCharArray().Select(x => Char.GetNumericValue(x));

edited Mar 17 '13 at 19:03

answered Mar 17 '13 at 18:38

ryan

6,541
5
43
68

+1 despite the fact that I hate LINQ, but your code looks cleaner ;) – Alina B. Mar 17 '13 at 18:39
@AlinaB. - what makes you hate linq? – Parimal Raj Mar 17 '13 at 18:40
That is not going to give what you want. It is going to print 49, 50, etc. – Mike Zboray Mar 17 '13 at 18:41
@AppDeveloper I don't know. Maybe I am to lazy to learn it ;) – Alina B. Mar 17 '13 at 18:41
its wrong , your array of int is : `{int[6]} [0]: 49 [1]: 50 [2]: 51 [3]: 52 [4]: 53 [5]: 54` – Parimal Raj Mar 17 '13 at 18:42
Sorry, I'm not in front of a compiler right now. Should be fixed now – ryan Mar 17 '13 at 18:45
The char `'1'` is different from the int `1`. Either subtract 48 from the char value or use `Char.GetNumericValue(x)` – Corak Mar 17 '13 at 18:53
2

If you know `integers` only contains the digits 0 through 9, then `x-'0'` would be *much* faster than `int.Parse(x)`. Also, the `var` keyword is causing the extremely misleading situation where `arrayOfInts` is the name of an `IEnumerable` that is definitely *not* an array. – Sam Harwell Mar 17 '13 at 18:56

KF2 · Answer 2 · 2013-03-17T18:47:12.553

1

try this:

int[] array = new int["123456".ToArray().Count()];
            int i = 0;
            foreach (var item in "123456".ToArray())
            {
                array[i++] = int.Parse(item.ToString());
            }

or

   int[] array = "123456".ToArray().Select(data=>(int)data).ToArray();

edited Mar 17 '13 at 18:47

answered Mar 17 '13 at 18:41

KF2

9,887
8
44
77

score 0 · Answer 3 · answered Mar 17 '13 at 18:38

0

{
    string s = "1234567890";
    var lst = new List<int>();

    for (int n = 0; n < s.Length; n++)
    {
        int x;
        if (int.TryParse(s[n].ToString(), out x))
            lst.Add(x);
    }

    int[] arr = lst.ToArray();
}

answered Mar 17 '13 at 18:38

Alina B.

1,256
8
18

What's wrong with this? -1 for a working solution sucks! – Alina B. Mar 17 '13 at 18:57

score 0 · Answer 4 · edited May 23 '17 at 11:57

If you are getting parameter as string then

The Linq Way :

string str_num = "123456"
var arrayOfInts = str_num.ToCharArray().Select(x => x - 48).ToArray();

for the above Linq expression it has been assumed that all character are between 48 & 57

Non Linq Way :

int[] GetIntArray(string str_num)
{
    int num = Int32.Parse(str_num);
    List<int> listOfInts = new List<int>();
    while(num > 0)
    {
        listOfInts.Add(num % 10);
        num = num / 10;
    }
    listOfInts.Reverse();
    return listOfInts.ToArray();
}

Solution extended from : How to split a number into individual digits in c#?

list of ints transform to array of integers

4 Answers4