Output shell script to log file

Question

I have a scheduled unix script that I want to log the output of. I am unable to edit the cron file due to the user interface restrictions, and I am unable to add >> logfile to the command. Is there something I can add within the script itself to send the output to a log?

{

printf poo

 #Do not change
PRINTF=/usr/bin/printf
MSMTP=/usr/local/bin/msmtp
MSMTPCONF=/var/etc/msmtp.conf

 #Can be changed
FROM="nas4free@usinfosec.com"
TO="dpatino@usinfosec.com"
MDIR="CaseData"
SUBJECT="$MDIR Backup Report"


} > /mnt/support/logs/$SUBJECT.log
#BODY="$(cat /mnt/support/logs/test.log)"
#$PRINTF "From:$FROM\nTo:$TO\nSubject:$SUBJECT\n\n$BODY" | $MSMTP --file=$MSMTPCONF -t

score 6 · Answer 1 · answered Jun 05 '13 at 09:52

6

Try

#!/bin/bash
exec > /tmp/myLog.log 2>&1
set -x

The log shows:

+ echo 'Hello World!'
Hello World!

answered Jun 05 '13 at 09:52

lanes

1,847
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19
19

score 3 · Answer 2 · answered Mar 18 '13 at 18:20

3

One way is to wrap your script in braces and redirect the output as shown below:

#!/bin/bash
{
# script contents here
echo running script
} > logfile

answered Mar 18 '13 at 18:20

dogbane

266,786
75
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414

I tried this and it worked until I added a variable in the logfile name. I've added my code to the question. – Daryl Patino Mar 18 '13 at 19:06
1

move the `SUBJECT` variable assignment outside the braces. – dogbane Mar 19 '13 at 08:14
@dogbane with this `>> logfile` I can append to the logfile, is it possible to "append to the top" in the logfile? Thanks a lot. – Jags Jul 16 '21 at 23:43

Vivek Goel · Answer 3 · 2013-03-19T03:20:43.363

0

Append following line in starting of your script

log_file_path="/tmp/output.log"
log() { while IFS='' read -r line; do echo "$line" >> "$log_file_path"; done; };
exec > >(tee >(log)) 2>&1

Your script with modification

PRINTF=/usr/bin/printf
MSMTP=/usr/local/bin/msmtp
MSMTPCONF=/var/etc/msmtp.conf
FROM="nas4free@usinfosec.com"
TO="dpatino@usinfosec.com"
MDIR="CaseData"
SUBJECT="$MDIR Backup Report"

{

printf poo  


} > /mnt/support/logs/$SUBJECT.log
#BODY="$(cat /mnt/support/logs/test.log)"
#$PRINTF "From:$FROM\nTo:$TO\nSubject:$SUBJECT\n\n$BODY" | $MSMTP --file=$MSMTPCONF -t

edited Mar 19 '13 at 03:20

answered Mar 18 '13 at 18:03

Vivek Goel

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I don't really understand what that's doing. I put that at the top of the script? – Daryl Patino Mar 18 '13 at 18:15
@DarylPatino Find better explanation here http://stackoverflow.com/questions/3173131/redirect-copy-of-stdout-to-log-file-from-within-bash-script-itself. – Vivek Goel Mar 18 '13 at 18:19
Thanks, that's for bash. I need something for sh. – Daryl Patino Mar 18 '13 at 18:39
@DarylPatino Please see updated answer. In your code you need to move variable out. So you can use variable in that scope. – Vivek Goel Mar 19 '13 at 03:21

Output shell script to log file

3 Answers3