how to print a certain number of bytes(characters) pointed by a pointer

Question

I have a pointer which point to a memory of 20 bytes, and then copy something to the memory

u_char* pkt=malloc(20);
memcpy(pkt, somecontent, 20);

I want to examine the 20 bytes starting from pkt so I want to print all the bytes with a format like 0xa6 how to do this in language C

thanks!

score 2 · Answer 1 · edited Mar 20 '13 at 18:36

2

int i=0;
for (; i<20; i++)
  printf("0x%.2x ", pkt[i]);
printf("\n");

edited Mar 20 '13 at 18:36

WhozCraig

answered Mar 20 '13 at 18:31

masoud

That is exactly what this man needed, but I'd also suggest him reading printf man pages, for example here: http://linux.die.net/man/3/printf – Sergey Savenko Mar 20 '13 at 18:33

score 0 · Accepted Answer · answered Mar 20 '13 at 18:34

0

The following code is sufficient,

int i=0;
u_char  * ptr=pkt;
for (; i<20; i++)
  printf("%x ", ptr++);
printf("\n");

answered Mar 20 '13 at 18:34

Deepu

2 Answers2