Decode JSON with square brackets

Question

I have tried to decode this json,but no luck,these square brackets are making me confused any help would be appreciated,here is my json

[{"location":[{"building":["Default Building"],"name":"Default Location"}],"name":"Default Organization"}]

Thank you

`$str = '[{"location":[{"building":["Default Building"],"name":"Default Location"}],"name":"Default Organization"}]'; print_r(json_decode($str));` It is valid JSON and square brackets means Array: http://www.json.org/ — Roman Newaza, Mar 21 '13 at 07:10
I think you are facing problem here "building": [ "Default Building" ], — Rohit Choudhary, Mar 21 '13 at 07:14
sir,i would like to take the value of each key separately ,how can i do that i dont want var_export — Sree, Mar 21 '13 at 07:23

Alireza · Accepted Answer · 2013-03-21T08:23:16.247

4

try this:

var_export( json_decode( '[{"location":[{"building":["Default Building"],"name":"Default Location"}],"name":"Default Organization"}]' )  );

json_decode return array or object . you can print it with var_export not echo

and you can access to values :

$items = json_decode('[{"location":[{"building":["Default Building"],"name":"Default Location"}],"name":"Default Organization"}]');

foreach( $items as $each ){
  echo $each->location[0]->building[0];
  echo '<hr />';
  echo $each->location[0]->name;
  echo '<hr />';
  echo $each->name; // default organization
}

edited Mar 21 '13 at 08:23

answered Mar 21 '13 at 07:13

Alireza

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Thank you all,@ Alireza41,how can i retrieve the value default organisation – Sree Mar 21 '13 at 07:58

score 1 · Answer 2 · answered Mar 21 '13 at 07:18

Your json is valid , might be you are facing problem while accessing the objects inside the array.

print_r is always a good friend to understand array structure . try this

    $json = '[{"location":[{"building":["Default Building"],"name":"Default Location"}],"name":"Default Organization"}]';
$decoded = json_decode($json);

echo '<pre>';
print_r($decoded);

$location = $decoded[0]->location;
$building = $location[0]->building[0];
$name = $location[0]->name;

Object at place 0 will only return the first item , if your array has multiple values then use foreach

score 0 · Answer 3 · answered Mar 21 '13 at 07:14

Seems its a valid JSON.

$my_json = '[{"location":[{"building":["Default Building"],"name":"Default Location"}],"name":"Default Organization"}]';
$my_data = json_decode($my_json);
print_r($my_data);

// Output

Array
(
    [0] => stdClass Object
        (
            [location] => Array
                (
                    [0] => stdClass Object
                        (
                            [building] => Array
                                (
                                    [0] => Default Building
                                )

                            [name] => Default Location
                        )

                )

            [name] => Default Organization
        )

)

score -1 · Answer 4 · answered Apr 05 '23 at 11:57

For this case, I prefer to add curly brackets before and after the string. It allows me then to use json_decode($json, true); which is my favorite way to interact with json variables.

  $my_json = '[{"location":[{"building":["Default Building"],"name":"Default Location"}],"name":"Default Organization"}]';
  $json = json_decode('{ "data":'.$my_json.'}', true);
  $my_data = $json['data'][0];
  print_r($my_data['location']);
  echo $my_data['location'][0]['building'][0];

Decode JSON with square brackets

4 Answers4