When I compile this code, it gives me
"[Error] unknown type name 'days' ". What am I doing wrong?
#include <stdio.h>
int main(void){
int k=0;
enum days {Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday};
days dayVariable;
printf("Enter number of the day: ");
scanf("%d",&k);
dayVariable=days(k);
printf("%s", dayVariable);
return 0;
}
If it's C, you must write:
enum days dayVariable;
...
dayVariable = (enum days)k;
If you want days to be the type name, typedef it:
typedef enum {Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday} days;
Other than that, you use the wrong format specifier in printf.
P.S.
And remember, C and C++ are different languages. It's obvious from your code and misconceptions that you come from some C++ background. Try to pick up a book on C programming.
enum is not string. Acutally Monday=0, Tuesday=1, etc. If you want to print string, you may do this:
char *days[] = {"Monday", "Tuesday", ... "Sunday"};
printf("%s", days[k]);
In C, enums aren't in the same namespace as normal types. If you want to define a variable typed as that enum, you can do:
enum days dayVariable;
Alternatively you can define a standard type for your enum. There are many similar ways to do that; here is one:
typedef enum {
/* ... */
} days;
This won't compile either:
dayVariable=days(k);
days is not a function, and in C in general type names (which you seem to expect days to be) are not functions either. You might mean:
dayVariable = (enum days) k;
In other words, using a simple cast to the proper type name.
