Can i write code like this
class Foo
{
typedef Foo type;
};
I don't see any limitations in standard about this.
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1Have you tried it? Seems to me the compiler should tell you quickly enough whether it works... – Nate Hekman Mar 21 '13 at 14:36
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1@NateHekman compilers don't always follow all the rules. – juanchopanza Mar 21 '13 at 14:40
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`Foo` symbol exists, so you can `typedef` it, so yes it works. – FredericS Mar 21 '13 at 14:50
2 Answers
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NOTE: Compiler: Apple GCC, OS: OSX 10.7
GCC finds nothing wrong with this, and I am able to use the type type later in the definition of Foo. However, you cannot use the type type outside of Foo.
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Because `class` keyword means private by default. But if declared public, you can access with `Foo::type`. – FredericS Mar 21 '13 at 14:49
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@FredericS: Yes. Just making it clear that everything is working as intended. – Linuxios Mar 21 '13 at 14:50
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It is possible to write that code. type and Foo are not reserved words, and C++ allows to define types within structs or classes. In fact, they are heavily used in templates for metaprogramming and type introspection. See How do you understand dependent names in C++ for further details on that aspect of the language.
