Passing PHP Variable into JavaScript Function

Question

I have the following code:

FB.getLoginStatus(function (response) {
    if (response.status === "connected") {
        FB.api("me/bookvote:download", "post", {

        }, //Missing a , here?

however, I am still getting:

 Uncaught SyntaxError: Unexpected identifier 
 for  book: "<?php echo "http://mysite.xom/auction_details.php?name=$item_details["name"]&auction_id=$item_details["auction_id"]";?>",

what could be wrong in my php variable to JavacScript?

Look at the colors in your code, are you sure you got those quotes right ? — adeneo, Mar 21 '13 at 22:36

score 3 · Answer 1 · answered Mar 21 '13 at 22:37

3

Wrap { } around your array items inside your string, like {$item_details["name"]}

answered Mar 21 '13 at 22:37

Uberfuzzy

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score 1 · Answer 2 · answered Mar 21 '13 at 22:37

Magic quotes are no longer supported. Change

book: "<?php echo "http://mysite.xom/auction_details.php?name=$item_details["name"]&auction_id=$item_details["auction_id"]";?>",

to

book: "<?php echo "http://mysite.xom/auction_details.php?name=" . $item_details["name"] . "&auction_id=" . $item_details["auction_id"];?>",

score 1 · Answer 3 · answered Mar 21 '13 at 22:38

You're not concatenating properly in your PHP code:

FB.getLoginStatus(function (response) {
    if (response.status === "connected") {
        FB.api("me/bookvote:download", "post", {
            book: "<?php echo 'http://mysite.xom/auction_details.php?name='. $item_details['name'] . '&auction_id=' . $item_details['auction_id']; ?>",
            fb:explicitly_shared = "true" //? Is syntactically valid but creates a global
        },

For readability, I replaced double quotes in your PHP code with single quotes.

Passing PHP Variable into JavaScript Function

3 Answers3