mysql select * or desired parameters in php function

Question

I have a function which selects the * values from a particular table, I need to configure that if I pass * in parameter then it selects all or the selected parameters.

My function is as follows:

  public function select($tablename){
          $select = mysql_query("SELECT * FROM $tablename");
          if(!$select){
              echo "cant select table mane";
              }
          while ($row = mysql_fetch_array($select)){

              print_r($row);
              }
          }

How can I pass the dynamic colum name in place of *

Avoid mysql, it is [deprecated](http://www.php.net/manual/en/intro.mysql.php). Use mysqli or PDO instead. — Alex, Mar 22 '13 at 12:20

score 1 · Answer 1 · answered Mar 22 '13 at 12:19

public function select($tablename,$column=NULL){
      if($column == null) {
          $select = mysql_query("SELECT *  FROM $tablename");
      } else {
          $select = mysql_query("SELECT ".$column."  FROM $tablename");
      }

call it using select("abcd_table","id,name"); OR for all just select("abcd_table");

By Alex

Avoid mysql, it is deprecated. Use mysqli or PDO instead

score 1 · Answer 2 · edited May 25 '19 at 14:25

Add one more parameter $columnname type array in your function.

   public function select($tablename,$columnname = array()){
      if(count($columnname)){
         $columnname = implode(",",$columnname);
         $select = mysql_query("SELECT {$columnname} FROM $tablename");
      }  
      else{
        $select = mysql_query("SELECT * FROM $tablename");
      }
      #code continue
   }

Calling will be like below

To select all fields,

select($tablename);

To select some fields,

select($tablename,array('field','field2'));

Note: Please, don't use mysql_* functions in new code. They are no longer maintained and are officially deprecated. See the red box? Learn about prepared statements instead, and use PDO, or MySQLi - this article will help you decide which. If you choose PDO, here is a good tutorial.

score 1 · Answer 3 · answered Mar 22 '13 at 12:29

That's even easier:

public function select( $tablename , $columnName = array() ){
   $columnName = $columnName ? implode( ',' , $columnName ) : '*';
   $select     = mysql_query( 'SELECT ' . $columnName . ' FROM ' . $tableName );
   if(!$select){
      echo "cant select table mane";
   }
   while ($row = mysql_fetch_array($select)){
      print_r($row);
   }
}

user7282 · Answer 4 · 2013-03-22T12:26:38.360

0

 public function select($tablename,$column="*"){

          $select = mysql_query("SELECT $column FROM $tablename");
          if(!$select){
              echo "cant select table mane";
              }
          while ($row = mysql_fetch_array($select)){

              print_r($row);
              }
          }

call like select("table","*") or call like select("table","col1,col2")

edited Mar 22 '13 at 12:26

answered Mar 22 '13 at 12:18

user7282

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score 0 · Answer 5 · answered Mar 22 '13 at 12:19

public function select($tablename, $selectrow){
          $select = mysql_query("SELECT $selectrow FROM $tablename");
          if(!$select){
              echo "cant select table mane";
          }
          while ($row = mysql_fetch_array($select)){
              print_r($row);
          }
}

score 0 · Answer 6 · answered Mar 22 '13 at 12:26

try this modified function

public function select($tablename,$array_fields){
    if(!empty($array_fields)){
      $fieldstr = implode(',',$array_fields);
      $fieldstr = trim($fieldstr,',');
    }else{
        $fieldstr = '*';
    }
      $select = mysql_query("SELECT $fieldstr FROM $tablename");
      if(!$select){
          echo "cant select table mane";
          }
      while ($row = mysql_fetch_array($select)){

          print_r($row);
          }

}

mysql select * or desired parameters in php function

6 Answers6