String to char - C++

Question

How can I convert a string to char?

I already Googled and I didn't find the answer to the situation I'm in. Really, I'm trying to convert an int to a char but my compiler doesn't support the to_string function so I decided to convert to from int to string then string to char.

I'm using a char[ ][ ] so I can store integers and chars.

stringstream ss;
ss << j; // j is the integer
string s(ss.str());
ascii_text[1][i] = (char)s;

EDIT:

I'm working with ASCII chars.

This is what I'm trying to do. int a = 10; -> string s = "10"; -> char c = '10';

I'll be happy if I found a way to convert int to char directly.

http://stackoverflow.com/questions/9655202/how-to-convert-integer-to-string-in-c — Dave, Mar 25 '13 at 20:13
How do you imagine the result to look like? A string consists of several `char`s. Which of those do you want? — Konrad Rudolph, Mar 25 '13 at 20:13
If the earlier comments are too subtle, you're asking "How do I convert a collection of characters into a single character?" That doesn't have a well-defined meaning. — Drew Dormann, Mar 25 '13 at 20:15
@DrewDormann Yeah, I still don't know how I can convert from int to char. — MosesA, Mar 25 '13 at 20:22
By the way, casting like that was the subject of a question asked earlier: http://stackoverflow.com/questions/15609575/type-cast-a-string-to-char-in-c — chris, Mar 25 '13 at 20:22
@AdegokeA edit your question so it clearly reflects *the question you have* — Drew Dormann, Mar 25 '13 at 20:25
It looks like you still don't understand exactly why `char c = '10'` is nonsense. A `char` is a data type designed to hold **one character**. You're trying to pour two cans of Diet Coke into an empty Diet Coke can. There's a mess on the floor now. — Drew Dormann, Mar 25 '13 at 20:30
I do. But how can I store integers and chars in the same 2D array? — MosesA, Mar 25 '13 at 20:32
@AdegokeA Given your new question in the comments, I recommend that you step back and analyze what the bigger problem is that you're trying to solve. It seems like what you're really trying to do is store an `int` as an array of ASCII characters, but I'm not sure. Each revised question has implied that you're trying to build on incorrect assumptions. Good luck. — Drew Dormann, Mar 25 '13 at 21:07

score 3 · Answer 1 · answered Mar 25 '13 at 20:14

3

If I understood you correctly, then all you want to do is get from an integer digit (0-9) to an ascii digit ('0'-'9')? In that case, char(j)+'0' will do.

answered Mar 25 '13 at 20:14

Cubic

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Have to add tens places too http://stackoverflow.com/a/7022827/195488 , if going to int – Mar 25 '13 at 20:16
@Cubic I already tried that and I got ASCII chars, like 20 would give be space instead of '20'. – MosesA Mar 25 '13 at 20:25
@AdegokeA That's because there's no character for the number 20. If you want a string, then you just take the string you already got. – Cubic Mar 25 '13 at 20:26
I'm using a char[][] so I can store integers and chars. See my problem? – MosesA Mar 25 '13 at 20:28
@AdegokeA No, I don't. I don't know what you're trying to do, but I think you're doing it wrong. – Cubic Mar 25 '13 at 20:39
Yeah, I am. I didn't have to use a 2D array. Thanks though. :) – MosesA Mar 25 '13 at 20:42

user123 · Answer 2 · 2013-03-25T20:27:08.630

3

How can I convert a string to char?

Okay. If you mean char*, then the std::string class has a c_str() method:

std::string myString = "hello";
const char* myStr = myString.c_str();

A char has a size of 1 byte, so you can't fit any string in it, unless that string has a length of 1. You can however get the char at a certain position in a string:

std::string str = "hi bro";
char c = str[0]; // This will be equal to 'h'

edited Mar 25 '13 at 20:27

answered Mar 25 '13 at 20:15

user123

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`std::string::c_str` returns a `const char*`. – Lightness Races in Orbit Mar 25 '13 at 20:22

score 0 · Answer 3 · answered Mar 25 '13 at 20:14

0

You should be able to just do

int j = 3;
char ch;
stringstream ss;
ss << j;
ss >> ch;

answered Mar 25 '13 at 20:14

DiegoNolan

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If string is "61", it only give '6' back. – MosesA Mar 25 '13 at 20:19
There is no string in my code. He is trying to convert an int, there is no reason for him to use a string. – DiegoNolan Mar 25 '13 at 20:24

score 0 · Answer 4 · answered Mar 25 '13 at 20:15

0

You can use the c_str() method to get an array of chars from string.

http://www.cplusplus.com/reference/string/string/c_str/

answered Mar 25 '13 at 20:15

Johnny Mnemonic

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String to char - C++

4 Answers4