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I'm using this example for a D3.js tree layout.

http://mbostock.github.com/d3/talk/20111018/tree.html

I need to flip it, so the root node is on the right hand side, and the links... etc.

How can I achieve this?

user1277546
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  • possible duplicate of [Tree drawing orientation](http://stackoverflow.com/questions/11673335/tree-drawing-orientation) – Ian Feb 09 '15 at 15:47

1 Answers1

8
  • Change the offset of each node to be from the right rather than offset from the left:

    // Normalize for fixed-depth.
    nodes.forEach(function(d) { d.y = d.depth * 180; });
    

Becomes:

    // Normalize for fixed-depth from right.
    nodes.forEach(function(d) { d.y = w - (d.depth * 180); });
  • Change the labels to be on the opposite sides

    nodeEnter.append("svg:text")
      .attr("x", function(d) { return d.children || d._children ? -10 : 10; })
      .attr("dy", ".35em")
      .attr("text-anchor", function(d) { return d.children || d._children ? "end" : "start"; })    
      .text(function(d) { return d.name; })
      .style("fill-opacity", 1e-6);
    

Becomes:

    nodeEnter.append("svg:text")
      .attr("x", function(d) { return d.children || d._children ? 10 : -10; })
      .attr("dy", ".35em")
      .attr("text-anchor", function(d) { return d.children || d._children ? "start" : "end"; })    
      .text(function(d) { return d.name; })
      .style("fill-opacity", 1e-6);
  • Make original position of the root node on the right hand side, rather than the left so first transition isn't weird:

    root = json;
    root.x0 = h / 2;
    root.y0 = 0;
    

Becomes:

    root = json;
    root.x0 = h / 2;
    root.y0 = w;

Fiddle: http://jsfiddle.net/Ak5tP/1/embedded/result/

minikomi
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