Are == and != operators compiler-generated?

Question

Do I need to provide == and/or != operators? I've read here: Why don't C++ compilers define operator== and operator!=? that I do but when I actually tried it (didn't provide them and tried to use them) the program compiled fine. So what's going on?

Using VS2010 if it matters.

How about showing us your code? It's hard to guess what you have done as my crystal ball broke just the other day ;) — Daniel Frey, Mar 31 '13 at 15:07

SomeWittyUsername · Answer 1 · 2013-03-31T14:58:32.583

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These operators are defined for fundamental, language-defined types, not for your custom ones. So it will work for ints, for example. But won't for class foo; unless you provide them explicitly - compiler doesn't know how to compare your own defined types if you haven't told it how to do it.

edited Mar 31 '13 at 14:58

answered Mar 31 '13 at 14:53

SomeWittyUsername

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Aren't these defined for floating-point numbers and pointers as well? – Mar 31 '13 at 14:54
@H2CO3 sure. `int` was an example – SomeWittyUsername Mar 31 '13 at 14:55
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@icepack: but you said "for integral types", and floating-point types and pointers are not integral. :) – jalf Mar 31 '13 at 14:55

Are == and != operators compiler-generated?

1 Answers1