How do I extract just the number from a named number (without the name)?

Question

I am looking for just the value of the B1(newx) linear model coefficient, not the name. I just want the 0.5 value. I do not want the name "newx".

newx <- c(0.5,1.5,2.5)

newy <- c(2,3,4)

out <- lm(newy ~ newx)

out looks like:

Call:
lm(formula = newy ~ newx)

Coefficients:
(Intercept)         newx  
       1.5         1.0

I arrived here. But now I am stuck.

out$coefficients["newx"]

newx 
 
1.0

as.numeric is does work. Maybe it is a low cost way to force out a number? — Andre Mikulec, Apr 01 '13 at 03:18
You can use the index number of `newx` (2) instead of the name like `out[[1]][[2]]`. — Gürol Canbek, Apr 28 '18 at 19:49

score 151 · Accepted Answer · answered Apr 01 '13 at 02:09

For a single element like this, use [[ rather than [. Compare:

coefficients(out)["newx"]
# newx 
#    1 

coefficients(out)[["newx"]]
# [1] 1

More generally, use unname():

unname(coefficients(out)[c("newx", "(Intercept)")])
# [1] 1.0 1.5

head(unname(mtcars))
#                     NA NA  NA  NA   NA    NA    NA NA NA NA NA
# Mazda RX4         21.0  6 160 110 3.90 2.620 16.46  0  1  4  4
# Mazda RX4 Wag     21.0  6 160 110 3.90 2.875 17.02  0  1  4  4
# Datsun 710        22.8  4 108  93 3.85 2.320 18.61  1  1  4  1
# Hornet 4 Drive    21.4  6 258 110 3.08 3.215 19.44  1  0  3  1
# Hornet Sportabout 18.7  8 360 175 3.15 3.440 17.02  0  0  3  2
# Valiant           18.1  6 225 105 2.76 3.460 20.22  1  0  3  1

## etc.

Pradeep Singh · Answer 2 · 2020-02-01T13:09:35.667

10

If the question is about removing names, another way is here

my_vec <- # some quantile function(returns named vector)
names(my_vec) <- NULL
my_vec
## [1] 1 2 3

edited Feb 01 '20 at 13:09

answered Feb 01 '20 at 12:47

Pradeep Singh

432
5
11

score 2 · Answer 3 · answered Jul 23 '21 at 07:49

2

An easy and rather direct way to do it is

as.numeric(out$coefficients["newx"])

answered Jul 23 '21 at 07:49

Álvaro A. Gutiérrez-Vargas

1,896
2
8
24

score 0 · Answer 4 · answered Oct 03 '20 at 18:56

0

Another way would be to use broom package:

broom::tidy(out)$estimate[1]
#1.5

answered Oct 03 '20 at 18:56

AlexB

3,061
2
17
19

1

A bit overkill, isn't it? Could you please shed some light on why this solution is more elegant/efficient than the accepted answer? I am asking from my utmost honest ignorance and not with a pedantic motif. – Álvaro A. Gutiérrez-Vargas Jul 23 '21 at 07:45

How do I extract just the number from a named number (without the name)?

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