NSString To NSNumber

Question

So this problem has been perplexing me for way too long. I have a UIAlertView with a textField in it, and I need the value of the textField as an NSNumber. But everything I try gives me random strings of numbers. Any help would be very much appreciated.

int i = [[alertView textFieldAtIndex:0].text intValue];
NSNumber *number = [NSNumber numberWithInt:[[alertView textFieldAtIndex:0].text integerValue]];    


int number = [[dict objectForKey:@"integer"] intValue];

NSLog(@"text = %@", [alertView textFieldAtIndex:0].text);


NSString *alertText = [alertView textFieldAtIndex:0].text;

NSNumberFormatter * f = [[NSNumberFormatter alloc] init];
[f setNumberStyle:NSNumberFormatterNoStyle];
NSNumber * myNumber = [f numberFromString:[alertView textFieldAtIndex:0].text];


NSNumber *number = @([alertText intValue]);

NSString *string = @"54";
NSNumber *number = @([string intValue]);

NSLog(@"here we are: %i", number);

related : http://stackoverflow.com/questions/1448804/how-to-convert-an-nsstring-into-an-nsnumber — DD_, Apr 01 '13 at 05:38
I saw that before asking. But when I ran that code, I got: `159348080 ` — Andrew, Apr 01 '13 at 05:39
please post your code,where you ar getting value from textfiled — Aman Aggarwal, Apr 01 '13 at 05:39
these all codes are not in the same method i guess. you defined both int number and NSNumber * number. it must give an error for redefinition — meth, Apr 01 '13 at 10:30

score 50 · Accepted Answer · edited Apr 25 '18 at 09:24

50

Once see this one,

NSString *string = @"123";
NSNumber  *aNum = [NSNumber numberWithInteger: [string integerValue]];
NSLog(@"%@",aNum);//NSString to NSNumber
NSInteger number=[string intValue];
NSLog(@"%i",number);//NSString to NSInteger

edited Apr 25 '18 at 09:24

Praveenkumar

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answered Apr 01 '13 at 05:54

Balu

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I think it was the `numberWithInteger` and `integerValue` parts that made it work for whatever reason. Anyway, Thanks a lot. – Andrew Apr 02 '13 at 01:34

score 7 · Answer 2 · edited Apr 01 '13 at 07:14

7

NSString *string = @"54";
NSNumber *number = @([string intValue]);
NSLog(@"here we are: %i", number);

Instead try using the following:

NSLog(@"here we are: %@", number);

Since you are converting to NSNumber (Object). You should use object specifier %@ in your NSLog statement.

edited Apr 01 '13 at 07:14

Anil

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answered Apr 01 '13 at 07:05

bpolat

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score 3 · Answer 3 · answered Apr 01 '13 at 05:36

3

Here's a sample with an integer and using NSNumber literals. You could also use the floatValue method if your string contains a float.

NSString *string = @"54";
NSNumber *number = @([string intValue]);

answered Apr 01 '13 at 05:36

Aaron Wojnowski

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Shouldn't the second line be, ***NSNumber *number = [NSNumber numberWithInt:[string intValue]];***? – EmptyStack Apr 01 '13 at 05:41
This uses NSNumber literals which amount to the same thing. – Aaron Wojnowski Apr 01 '13 at 05:41
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Oooopssss. Use "%@" since it's an object. *facepalm* – Aaron Wojnowski Apr 01 '13 at 05:44

score 3 · Answer 4 · edited Apr 25 '18 at 09:25

3

@Aaron Wojnowski,

Use NSNumberFormatter If you want, you can set grouping separator also.

NSNumberFormatter *formatString = [[NSNumberFormatter alloc] init];
stringValue = textfield.text;
NSNumber *reqNumber = [formatString numberFromString:stringValue];

edited Apr 25 '18 at 09:25

Praveenkumar

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answered Apr 01 '13 at 05:42

Ramu Pasupuleti

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NSString To NSNumber

4 Answers4