syntax error on `If` line

Question

My code:

#!/usr/bin/env python

def Runaaall(aaa):
  Objects9(1.0, 2.0)

def Objects9(aaa1, aaa2):
  If aaa2 != 0: print aaa1 / aaa2

The error I receive:

$ python test2.py 
  File "test2.py", line 7
    If aaa2 != 0: print aaa1 / aaa2
          ^
SyntaxError: invalid syntax

I'm at a loss to why this error is happening.

@S.Lott: :) I guess he hasn't followed your advice here http://stackoverflow.com/questions/1573548/python-def-function-how-do-you-specify-the-end-of-the-function — SilentGhost, Oct 15 '09 at 20:35
@SilentGhost: Good point. I rarely check to see who asks the question. This appears to be two questions with the same bad behavior: type random stuff and hope it works. — S.Lott, Oct 16 '09 at 00:16

score 16 · Accepted Answer · edited Oct 15 '09 at 20:32

if must be written in lower case.

Furthermore,

Write function names in lower case (see PEP 8, the Python style guide).
Write the body of an if-clause on a separate line.
Though in this case you'll probably not run into trouble, be careful with comparing floats for equality.
Since you've just started learning Python, you may want to get acquainted with writing parentheses around the arguments to print, since from Python 3 onwards, print is a function, not a keyword.
To enforce this syntax in Python 2.6, you can put this at the top of your file:
```
from __future__ import print_function
```
Demonstration:
```
>>> print 'test'
test
>>> from __future__ import print_function
>>> print 'test'
  File "<stdin>", line 1
    print 'test'
               ^
SyntaxError: invalid syntax
>>> print('test')
test
```
For more on __future__ imports, see the documentation.

the last point can be achieved by using from __future__ import print_function on python 2.6 — Bartosz Radaczyński, Oct 15 '09 at 20:07
Good point, Bartosz. I updated the answer with some more information. — Stephan202, Oct 15 '09 at 20:35

score 4 · Answer 2 · answered Oct 15 '09 at 19:32

4

It's the capital 'I' on "If". Change it to "if" and it will work.

answered Oct 15 '09 at 19:32

steveha

score 3 · Answer 3 · answered Oct 15 '09 at 19:31

3

How about

def Objects9(aaa1, aaa2):
  if aaa2 != 0: print aaa1 / aaa2

Python keywords are case sensitive, so you must write 'if' instead of 'If', 'for' instead of 'fOR', et cetera.

answered Oct 15 '09 at 19:31

David Seiler

3 Answers3