AngularJS filter array

Question

Let say I have an array object

[{
    name: 'a',
    number: 1
},
{
    name: 'b',
    number: 2
},
{
    name: 'c',
    number: 3
}]

And I just want to get the name:'b' which is array[1] values. How to pass it to the filter?

<li ng-repeat="foo in foos | filter:what_to_do_here="b"><li>

score 20 · Accepted Answer · answered Apr 02 '13 at 06:17

20

<li ng-repeat="foo in foos | filter:{name:'b'}">{{foo.name}}</li>

answered Apr 02 '13 at 06:17

Stewie

1

suppose there's another object in the list `{name:'abc',number:100}`, then this filter will also select this object because it contains `b` in `name` attributes. is there anyway to alter the comparison behavior from 'contains' to exact match? – Bilal Mirza Sep 12 '13 at 11:04
Is there anyway to apply a not filter to this? For example, all objects whose name is not 'b'? – Conqueror Nov 07 '13 at 22:19
Yes, prepend the search string with `!`: `
{{foo.name}}

score 1 · Answer 2 · answered Apr 02 '13 at 09:16

1

<li ng-repeat="foo in foos | filter:'b'">{{foo.name}}</li>

might work as well

answered Apr 02 '13 at 09:16

Aladdin Mhemed

Sure, but vzhen wants to filter by `name` explicitly. – Stewie Apr 02 '13 at 12:29

2 Answers2