Default task for namespace in Rake

Question

Given something like:

namespace :my_tasks do
  task :foo do
    do_something
  end

  task :bar do
    do_something_else
  end

  task :all => [:foo, :bar]
end

How do I make :all be the default task, so that running rake my_tasks will call it (instead of having to call rake my_tasks:all)?

have you tried putting a default into the namespace (task :default => :all) — Jim Deville, Oct 16 '09 at 17:10
Do what Jim describes, only the default task goes outside the namespace and must include the namespace and task name. (task :default => "my_tasks:all") See my answer below for a working example. — Randy Eppinger, May 13 '13 at 01:02

score 89 · Accepted Answer · edited Jun 18 '13 at 18:30

89

Place it outside the namespace like this:

namespace :my_tasks do
  task :foo do
    do_something
  end

  task :bar do
    do_something_else
  end

end

task :all => ["my_tasks:foo", "my_tasks:bar"]

Also... if your tasks require arguments then:

namespace :my_tasks do
  task :foo, :arg1, :arg2 do |t, args|
    do_something
  end

  task :bar, :arg1, :arg2  do |t, args|
    do_something_else
  end

end

task :my_tasks, :arg1, :arg2 do |t, args|
  Rake::Task["my_tasks:foo"].invoke( args.arg1, args.arg2 )
  Rake::Task["my_tasks:bar"].invoke( args.arg1, args.arg2 )
end

Notice how in the 2nd example you can call the task the same name as the namespace, ie 'my_tasks'

edited Jun 18 '13 at 18:30

Daithí

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answered Oct 16 '09 at 17:13

Szymon Lipiński

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That only makes it available to be called as `rake all`. In this case, I have other namespaces, so what I want is to be able to call the task `my_tasks:all` as `rake my_tasks`, not as `rake all`. – agentofuser Oct 16 '09 at 17:20
53

so then just use: task :my_tasks => ["my_tasks:foo", "my_tasks:bar"] – Szymon Lipiński Oct 16 '09 at 19:07
2

Up voted for simon's comment, I had forgotten that this is how I do it. – Jim Deville Oct 16 '09 at 19:15

score 52 · Answer 2 · edited Mar 13 '17 at 21:56

52

Not very intuitive, but you can have a namespace and a task that have the same name, and that effectively gives you what you want. For instance

namespace :my_task do
  task :foo do
    do_foo
  end
  task :bar do
    do_bar
  end
end

task :my_task do
  Rake::Task['my_task:foo'].invoke
  Rake::Task['my_task:bar'].invoke
end

Now you can run commands like,

rake my_task:foo

and

rake my_task

edited Mar 13 '17 at 21:56

Gabriel Lett

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answered Jan 20 '12 at 09:03

Shyam Habarakada

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3

this is great and covers all the requirements stated in the question. – Ivar Jan 08 '14 at 19:20
1

I think the invocation is overly complicated and it should just be task dependencies: `task :my_task => ['my_task:foo', 'my_task:bar']` – Alexander Presber Feb 25 '20 at 13:24

score 9 · Answer 3 · edited Feb 26 '21 at 21:45

9

I suggest you to use this if you have lots of tasks in the namespace.

task :my_tasks do
  Rake.application.in_namespace(:my_tasks){|namespace| namespace.tasks.each(&:invoke)}
end

And then you can run all tasks in the namespace by:

rake my_tasks

With this, you don't need to worry to change your :all task when you add new tasks into that namespace.

edited Feb 26 '21 at 21:45

Joshua Pinter

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answered Jun 09 '13 at 06:02

Rocky

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THANK YOU!! FFS, I was looking for something like this. Manually having to update the "parent" task with any changes or additions is brutal, especially if the tasks are kept in separate files due to their length. This is so much better. Bravo. – Joshua Pinter Feb 26 '21 at 21:10
For what it's worth, the `x` is of `Rake::NameSpace` class. I updated your answer to reflect this and be more explicit. – Joshua Pinter Feb 26 '21 at 21:14
Also updated your answer to use the shorthand `.each(&:invoke)`. – Joshua Pinter Feb 26 '21 at 21:45

score 4 · Answer 4 · answered May 13 '13 at 00:58

4

I use this Rakefile for cucumber:

require 'cucumber'
require 'cucumber/rake/task'

namespace :features do
  Cucumber::Rake::Task.new(:fast) do |t|
    t.profile = 'fast'
  end

  Cucumber::Rake::Task.new(:slow) do |t|
    t.profile = 'slow'
  end

  task :ci => [:fast, :slow]
end

task :default => "features:ci"

Then if I type just:

rake

It runs the default task, which runs both fast and slow tests.

I learned this from Cheezy's blog.

answered May 13 '13 at 00:58

Randy Eppinger

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OP didn't want to change the global default, they wanted to change the namespace default. – JBallin Mar 15 '22 at 22:54

zor-el · Answer 5 · 2019-10-26T07:00:15.017

The way I'm reading obvio171's question is that he is asking¹⁾ for a systematic way to invoke a certain task in a namespace by invoking the namespace as a task.

I've frequently encountered the same need. I like to logically group tasks into namespaces. Often that grouping resembles a hierarchy. Hence the desire to invoke the group makes very much sense to me.

Here's my take:

module Rake::DSL
  def group(name, &block)
    ns = namespace name, &block
    default = ns[:default]
    task name => "#{name}:default" if default
    ns
  end
end

group :foo do
  task :foo1 do |t| puts t.name end
  task :foo2 do |t| puts t.name end
  task :default => [:foo1, :foo2]
end

task :default => :foo

¹⁾...or was asking, years ago. Nonetheless a still interesting question.

tvw · Answer 6 · 2015-09-02T16:06:20.893

Add the following task outside of the namespace:

desc "Run all my tasks"
task :my_tasks => ["my_tasks:all"]

Keep in mind, that you can have a task with the same name as the namespace.

And hier a bigger example, that shows, how you can make use of tasks, which have the same name as the namespace, even when nesting namespaces:

namespace :job1 do
  task :do_something1 do
        puts "job1:do_something1"
    end

  task :do_something2 do
        puts "job1:do_something2"
    end
  task :all => [:do_something1, :do_something2]
end

desc "Job 1"
task :job1 => ["job1:all"]

# You do not need the "all"-task, but it might be handier to have one.
namespace :job2 do
  task :do_something1 do
        puts "job2:do_something1"
    end

  task :do_something2 do
        puts "job2:do_something2"
    end
end

desc "Job 2"
task :job2 => ["job2:do_something1", "job2:do_something2"]

namespace :superjob do
    namespace :job1 do
        task :do_something1 do
            puts "superjob:job1:do_something1"
        end

        task :do_something2 do
            puts "superjob:job1:do_something2"
        end
    end

    desc "Job 1 in Superjob"
    task :job1 => ["job1:do_something1", "job1:do_something2"]

    namespace :job2 do
        task :do_something1 do
            puts "superjob:job2:do_something1"
        end

        task :do_something2 do
            puts "superjob:job2:do_something2"
        end
    end

    desc "Job 2 in Superjob"
    task :job2 => ["job2:do_something1", "job2:do_something2"]
end

desc "My Super Job"
task :superjob => ["superjob:job1", "superjob:job2"]

# Do them all just by calling "$ rake"
task :default => [:job1, :job2, :superjob]

Just copy it and try it out.

score 0 · Answer 7 · edited May 23 '17 at 12:25

Based on Rocky's solution Default task for namespace in Rake

And this dexter's answer Is there a way to know the current rake task?

namespace :root do
  namespace :foo do
  end

  namespace :target do
    task :all do |task_all|
      Rake.application.in_namespace(task_all.scope.path) do |ns|
        ns.tasks.each { |task| task.invoke unless task.name == task_all.name } 
      end
    end

    task :one do
    end

    task :another do
    end
  end
end

score 0 · Answer 8 · answered Feb 25 '20 at 13:28

Combining Szymon Lipiński's and Shyam Habarakada's answers, here is what I think is the most idiomatic and consise answer:

namespace :my_tasks do
  task :foo do
    do_something
  end

  task :bar do
    do_something_else
  end

end

task :my_tasks => ["my_tasks:foo", "my_tasks:bar"]

allows you to do rake my_tasks while avoiding cumbersome invocation of the subtasks.

Default task for namespace in Rake

8 Answers8

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