Based roughly on your comments, you want something along the lines of this function:
/* return the fd or negative on error (check errno);
how is 1 if created, or 0 if opened */
int create_or_open (const char *path, int create_flags, int open_flags,
int *how) {
int fd;
create_flags |= (O_CREAT|O_EXCL);
open_flags &= ~(O_CREAT|O_EXCL);
for (;;) {
*how = 1;
fd = open(path, create_flags);
if (fd >= 0) break;
if (errno != EEXIST) break;
*how = 0;
fd = open(path, open_flags);
if (fd >= 0) break;
if (errno != ENOENT) break;
}
return fd;
}
This solution is not bullet proof. There may be cases (symbolic links maybe?) that would cause it to loop forever. Also, it may live-lock in certain concurrency scenarios. I'll leave resolving such issues as an exercise. :-)
In your edited question, you pose:
I have 10 processes which try open the same file more or less at the same time using open(O_CREAT) call, then delete it.
A hack-ish, but more bullet proof, solution would be to give each process a different user ID. Then, just use the regular open(path, O_CREAT|...)
call. You can then query the file with fstat()
on the file descriptor, and check the st_uid
field of the stat
structure. If the field equals the processes' user ID, then it was the creator. Otherwise, it was an opener. This works since each process deletes the file after opening.