Serializing Typesafe Config objects

Question

I'd like to persist a Config object (https://github.com/typesafehub/config) as a serialized string(maybe JSON ??) and read it back when required. However, I didnt find any API on the Config api docs that supports. Any help on this is appreciated.

I tried

config.toString

but the result looks like

Config(SimpleConfigObject({...data}))

score 69 · Accepted Answer · answered May 25 '13 at 03:33

69

Try this:

config.root().render(ConfigRenderOptions.concise())

answered May 25 '13 at 03:33

Sasha O

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+1, and Java serialization is also supported, if that's better for a given application. – Havoc P Jun 25 '13 at 18:56
This also gives everything else besides my config in application.conf. so how can I json pretty print only the config from my application.conf? – user1870400 Mar 30 '18 at 20:32
@user1870400 if you really just want `application.conf` you can use `ConfigFactory.parseResourcesAnySyntax("application.conf")` - but this won't substitute any environment variables or system properties. You might look at https://stackoverflow.com/questions/18195527/typesafe-config-load-additional-config-from-path-external-to-packaged-scala-app for some other options. – tilde Dec 22 '20 at 20:09
@user1870400 if you wrap everything in your `application.conf` in a top level object `myapp { ... }` you could do something like `ConfigFactory.load().getConfig("myapp").root().render( ... )`. – tilde Dec 22 '20 at 20:24

score 4 · Answer 2 · answered Aug 06 '20 at 15:30

4

Of course you can also adjust a few parameters, for example:

val renderOptions = ConfigRenderOptions
  .defaults()
  .setOriginComments(false)
  .setComments(false)
  .setFormatted(true)

println(config.root().render(renderOptions))

answered Aug 06 '20 at 15:30

Twistleton

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Serializing Typesafe Config objects

2 Answers2