JOptionPane Multidimensional Array output

Question

Ok say I have Multidimensional array that I want to display in JOptionPane.showMessageDialog. I know that when using System.out.println, you use a for loop. However the array size is determined by the user input, therefore I have to use a incrementor.

For example: userinput[k] next to usernumber[k] then the next row would be userinput[k+1] next to usernumber[k+1]

The trouble I am having is that by using my loop, it does each set one at a time in separate windows and not all together in a table in one window.

for (int k = 0; k < userinput.length; k++){
    JOptionPane.showMessageDialog(null, userinput[k]);
}

for (int k = 0; k < 2; k++){
    JOptionPane.showMessageDialog(null, usernumber[k]);
}

MadProgrammer · Answer 1 · 2013-04-05T00:48:07.423

2

Build your output into a single String.

You can use html tags to provide additional formatting

StringBuilder sb = new StringBuilder(64);
sb.append("<html><table>");
for (int ui = 0; ui = < userinput.length; ui++) {
    sb.append("<tr><td>");
    sb.append(userinput[ui]);
    sb.append("</td>");
    for (int k = 0; k < 2; k++){
        sb.append("<td>");
        sb.append(usernumber[k]);
        sb.append("</td>");
    }
    sb.append("</tr>");
}
sb.append("</table></html>");
JOptionPane.showMessageDialog(null, sb.toString());

edited Apr 05 '13 at 00:48

answered Apr 05 '13 at 00:36

MadProgrammer

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I'm messing around with what you provided. Is there a reason why it says it can't find the symbol sb.toString when compiling? – Chris Apr 05 '13 at 00:47
Sorry, missed the `()` - `toString` is a method :P - I've updated the answer – MadProgrammer Apr 05 '13 at 00:48

score 1 · Answer 2 · answered Apr 05 '13 at 00:34

1

Use a StringBuilder and concatenate each element of the array into a display message,

answered Apr 05 '13 at 00:34

Reimeus

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JOptionPane Multidimensional Array output

2 Answers2

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