how to make variables preserved after endlocal command

Question

Thanks Nate. It works.
But now i need output variable for this script to use later.
There are 2 outputs i need. First is count variable as integer output, second is string variable which is equal to last string character in "word".
So, i need this 2 variable as you see in last row of finished script before "press any key to continue...".
1 last integer variable and 1 last string variable.

I need these 2 variables for later scripting in this script.
How i can have it? Here is a script which works from yesterday.

@ECHO OFF
:input
set /p word=input your word:
if not defined word goto input
(ECHO %word%)> tempfile.txt
FOR %%x IN (tempfile.txt) DO ( SET /A lenght=%%~zx - 2 )

del tempfile.txt
echo %word% got %lenght% characters
setlocal enabledelayedexpansion

for /l %%m in (1,1,!lenght!) do (
  set /a count=%%m
  set /a index=%%m-1
  call echo !count! %%word:~!index!,1%%
) 

(call echo %%word:~!index!,1%%)>tf.txt


for /f "tokens=*" %%a in (tf.txt) do (
set line=%%a
set char=!line:~0,1!

)

pause

echo %count% %char%

endlocal

pause

the forum soft did obstuct me formatting your question better. please do it yourself. — Endoro, Apr 06 '13 at 09:07
look on this finished code. works when endlocal is at the end. i got 2 variables( one last integer and one last string ). but not working if i put endlocal after create tf.txt. can you make work on this way if endlocal is in next line after creation of tf.txt? — Zvonimir, Apr 06 '13 at 14:26

BDM · Answer 1 · 2013-04-06T10:58:36.243

2

There are many ways documented here that show how to do this, however endlocal & set global=local is my favourite.

Judging by what I think you want...

setlocal enabledelayedexpansion
for /l %%m in (1,1,!lenght!) do (
    set /a count=%%m
    set /a index=%%m-1
    call echo !count! %%word:~!index!,1%%
    set laststring=%word:~!index!,1%
) 
(
    endlocal
    set count=%count%
    set laststring=%laststring%
)

edited Apr 06 '13 at 10:58

answered Apr 06 '13 at 09:00

BDM

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Ah, but `endlocak&set global=%local%` is more likely to produce the desired results... :) – Magoo Apr 06 '13 at 09:09
1

can somebody finish this script on way i asked, cause i dont know? – Zvonimir Apr 06 '13 at 09:24
@Zvonimir What variables do you want to keep, and what variables do you want to save them as? – BDM Apr 06 '13 at 09:26
i want to keep last counter number and last string character – Zvonimir Apr 06 '13 at 09:27
@Zvonimir I can't make out what you mean by that. Do you want `%count%` and `%index%`, or do you want something completely different. Edited the question to reflect what I mean. – BDM Apr 06 '13 at 09:28
i want %count% and some %laststring% witch not defined – Zvonimir Apr 06 '13 at 09:33
@Zvonimir What do you want `%laststring%` to contain? – BDM Apr 06 '13 at 09:35
i want to contain last character from echo in this script – Zvonimir Apr 06 '13 at 09:37
this will be the index position character, but character as string – Zvonimir Apr 06 '13 at 09:40
@Zvonimir So should `%laststring%` have the value of `%%word:~!index!,1%%`, or `%index%`? – BDM Apr 06 '13 at 09:42
it must be value of %%word:~!index!,1%% – Zvonimir Apr 06 '13 at 09:47
for example if word was "qwertz" it must be "z" – Zvonimir Apr 06 '13 at 09:47
i must use this "z" and %count% in later calculation, so i need to have them as 2 variables, "z" is string variable; %count% is integer variable – Zvonimir Apr 06 '13 at 09:50
@Zvonimir Edited it. Does it look right? – BDM Apr 06 '13 at 10:12
i tried to echo these 2 variables, but doesnt work. i make: echo %count %laststring% but no good echoing?!? – Zvonimir Apr 06 '13 at 10:43
echo %count% %laststring% echoing "laststring"?!? – Zvonimir Apr 06 '13 at 10:54
@Zvonimir What about now? – BDM Apr 06 '13 at 10:58
doesnt work, echoing only "laststring" – Zvonimir Apr 06 '13 at 11:07
In case of `delayedexpansion` this will never work so. You need an other technique to break through the wall! – Endoro Apr 06 '13 at 11:28
like ever in batch, a for loop will help. – Endoro Apr 06 '13 at 11:36
please construct this work if you know how. you helped me with "call" 2 days ago. – Zvonimir Apr 06 '13 at 11:37
go shopping now, later back :-) – Endoro Apr 06 '13 at 11:42
1

Read here [SO:Make an environment variable survive ENDLOCAL](http://stackoverflow.com/q/3262287/463115) for different solutions – jeb Apr 06 '13 at 11:57
thanks for link but too complicated on this way for me. i dont have enough knowledge to understand all of that. just trying to understand how can i have variable stay after this situation. – Zvonimir Apr 06 '13 at 12:32
so i put that last character in txt.file with (call echo %%word:~!index!,1%%)>tf.txt last character is now only character in tf.txt is it way to load this character in batch file after endlocal, as string variable??? – Zvonimir Apr 06 '13 at 13:41
1

There are many situations where this method will fail. See answers to http://stackoverflow.com/q/3262287/1012053 for more reliable methods. – dbenham Apr 06 '13 at 15:51

score 1 · Accepted Answer · edited May 23 '17 at 12:33

1

Try this technic to tear down the wall of setlocal enabledelayedexpansion / endlocal:

@echo off&setlocal
set "word=abcdefghij"
set /a lenght=10

for /l %%m in (1,1,%lenght%) do (
    set /a $count=%%m
    set /a index=%%m-1
    setlocal enabledelayedexpansion
    call echo !$count! %%word:~!index!,1%%
    call set "$laststring=%%word:~!index!,1%%"
    for /f %%i in ('set $') do (if "!"=="" endlocal)& set "%%i"
)
echo( 
echo !$count! !$laststring!
echo %$count% %$laststring%

(source)

edited May 23 '17 at 12:33

Community

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answered Apr 06 '13 at 18:37

Endoro

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I only can say, that you make it again. do you sleep on book instead of pillow? you are genious. please if you can send me via mail brief explanation of every piece of your code i will be very greatfull to you. mail is zeusaluminium@gmail.com . – Zvonimir Apr 07 '13 at 07:56
i mean thoroughly and slow explanation. i was thinking that "brief"=slow and thoroughly, so type in google and find out that i use this word for wrong purpose:). learn every day:) – Zvonimir Apr 07 '13 at 08:09
`delayed expansion` doesn't mean "slow", it means "later" :) – Endoro Apr 07 '13 at 08:27
if i enebledelayedexpansion does this mean that all variables with !(exclamation mark) will developed at the same time in eni position in that block of enabledelayedexpansion?? – Zvonimir Apr 07 '13 at 08:49
delayed expansion means, the parser doesn't interpret `!variable!`s. Example: `@echo off ` `setlocal ` `set "uglyvar=^^&!&dir" ` `setlocal enabledelayedexpansion ` `echo !uglyvar! ` `pause ` `echo %uglyvar% ` ` ` – Endoro Apr 07 '13 at 09:00
who is parser in your code? – Zvonimir Apr 07 '13 at 09:12
Please see [here](http://stackoverflow.com/a/4095133/2098699), how does the parser work. – Endoro Apr 07 '13 at 09:21
thanks, i need at least two days to put these things in my head. so on tuesday i will be back on this article if will have something to ask. you helped me a lot with your time and examples;) – Zvonimir Apr 07 '13 at 09:34

how to make variables preserved after endlocal command

2 Answers2