Rounding double value into two significant digits in java

Question

I want to get a function which rounds the double value into two significant digits now i m using the below function

private static DecimalFormatSymbols DFS;
private static DecimalFormat myFormatter;
public static String DoubleToFormatedString(double value) {
    DFS = new DecimalFormatSymbols();
    DFS.setDecimalSeparator('.');
    myFormatter = new DecimalFormat("############.##");
    myFormatter.setDecimalFormatSymbols(DFS);
    return myFormatter.format(value);
}

but with this function eg: i m getting a rounded number 2.6, i need to get this like 2.60. '0'should come to the right of 1 significant num. what change should make? or any other way plz help me

From the documentation (http://docs.oracle.com/javase/1.4.2/docs/api/java/text/DecimalFormat.html) '0': Digit, '#': Digit, zero shows as absent — Vincent van der Weele, Apr 08 '13 at 07:58

score 2 · Accepted Answer · edited May 23 '17 at 10:25

2

Replace your formatter as below

myFormatter = new DecimalFormat("#.00");

For further details you can refer to this SO question : Format double to 2 decimal places with leading 0s

edited May 23 '17 at 10:25

Community

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1

answered Apr 08 '13 at 08:02

prashant

1,805
12
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score 0 · Answer 2 · answered Apr 08 '13 at 07:57

0

try

new DecimalFormat("#.00");

answered Apr 08 '13 at 07:57

Evgeniy Dorofeev

133,369
30
199
275

score 0 · Answer 3 · answered Apr 08 '13 at 08:01

0

Yes just use

DecimalFormat myFormatter = new DecimalFormat("#.00");

instead of

 DecimalFormat myFormatter = new DecimalFormat("############.##");

answered Apr 08 '13 at 08:01

Festus Tamakloe

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Rounding double value into two significant digits in java

3 Answers3