this is my table
id | question |
id's are grouped as
1000 -> 1050
2000 -> 2030
3000 -> 3099
4000 -> 4500
5000 -> 5010
I have to extract 5 records and one for each group of id.
How can I perform this with only one query?
Thanks a lot.
this is my table
id | question |
id's are grouped as
1000 -> 1050
2000 -> 2030
3000 -> 3099
4000 -> 4500
5000 -> 5010
I have to extract 5 records and one for each group of id.
How can I perform this with only one query?
Thanks a lot.
SELECT f1, f2, ... FROM tablename WHERE id BETWEEN 1000 AND 1050 ORDER BY RAND() LIMIT 1
UNION
SELECTS f1, f2, ... FROM tablename WHERE id BETWEEN 2000 AND 2030 ORDER BY RAND() LIMIT 1
UNION
SELECTS f1, f2, ... FROM tablename WHERE id BETWEEN 2000 AND 2030 ORDER BY RAND() LIMIT 1
and two more selects with UNION
SELECT *, IF (id > 1000 AND id < 1050, 1,
IF (id > 2000 AND id < 2030, 2,
IF (id > 3000 AND id < 3099, 3,
IF (id > 4000 AND id < 4500, 4,
IF (id > 5000 AND id < 5010, 5, 0))))) AS param
FROM questions WHERE param > 0 GROUP BY param
To do this with just one query (without using UNION
as was suggested by NedretRecap), you can add group_id
(or similar column) to your table and use simple ... GROUP BY group_id
.
Assuming that the reserved group size is always the same (it's not possible that some groups will start at +1000
from previous, and other at +300
) you could probably use this simple hack:
SELECT id
FROM table
GROUP BY FLOOR(id/1000)
Working example here.