Passing shared_ptr via variable argument list

Question

Is this possible to do and how would I pass the shared_ptr(s)? I found some related question (C++ variable number of arguments) but it does not fully address my question. I have tried a few ways to write such function but all I get is an error error: cannot receive objects of non-trivially-copyable type ‘class std::shared_ptr<Item>’ through ‘...’;

If this is not a good idea at all, how could I pass an arbitrary number of shared_ptr's as an an argument, almost something like variadic templates or such? Maybe this is even more simple than I think ...

Thanks for your help!

I agree with @DavidBrown. [Why not using variadic templates](http://stackoverflow.com/a/15465877/1932150)? — Andy Prowl, Apr 09 '13 at 18:44
@DavidBrown: I have never used variadic templates, so I am not sure if it would work (actually I have not tried it yet). — Andreas W. Wylach, Apr 09 '13 at 18:45

score 1 · Accepted Answer · answered Apr 09 '13 at 18:47

1

With C++11 you can either use variadic templates or initializer lists. Initializer lists are a bit easier to use, because they do not require recursion and they can be defined in separate compilation units:

void foobar(std::initializer_list<std::shared_ptr<widget>> widgets);

std::shared_ptr<widget> foo;
std::shared_ptr<widget> bar;
foobar({ foo, bar });

answered Apr 09 '13 at 18:47

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The initializer_list seems also to be an nice option! I will try that too. – Andreas W. Wylach Apr 09 '13 at 18:51
I finally tried this out (also with variadic template) and it seems to work. Thanks for the hint. I just need to get more into the C++11 Details and options ... – Andreas W. Wylach Apr 10 '13 at 09:06

Passing shared_ptr via variable argument list

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