subprocess popen, how to get access?

Question

I'm trying to write a python script that starts a subprocess, and writes to the subprocess' stdin.
Here I can write and get a result:

def get_band():
    print "band" 
    p = subprocess.Popen(["/path/to/program","-c","-"], stdout=subprocess.PIPE, stdin=subprocess.PIPE, stderr=subprocess.PIPE)
    ran_stdout = p.communicate(input='show status')[0]
    print(ran_stdout)

However the print statement gives:

Unable to connect at 127.0.0.1, Connection refused.

If I do this the same result is displayed:

p = subprocess.Popen(["/path/to/program","-c","-"], stdout=subprocess.PIPE, stdin=subprocess.PIPE, stderr=subprocess.PIPE).communicate()
print p[0]

If I run this command from a terminal it works fine, I can get the result back.

What is wrong with the parameters given? ["/path/to/program","-c","-"]

Isn't this a problem with `["/path/to/program","-c","-"]` not subprocess? — danodonovan, Apr 10 '13 at 09:22
So, whatever 'path/to/program' is, it is producing the error you provide (it seems to be unable to connect to localhost). Surely you should be looking at correcting the program 'path/to/program'? — danodonovan, Apr 10 '13 at 09:36
possible duplicate of [writing to stdin, access denied](http://stackoverflow.com/questions/15906833/writing-to-stdin-access-denied) — glglgl, Apr 10 '13 at 09:41
taht turned into how to write multiple commands so I separated them — Paul, Apr 10 '13 at 09:44
seems this is some sort of permissions error, so maybe the question cant be answered here. — Paul, Apr 10 '13 at 09:45

score 0 · Accepted Answer · answered Apr 10 '13 at 10:49

0

This worked for some reason, passing in the command in the same line.

  p = subprocess.Popen(["/path/to/program", '-c', '-', cmd_here],
  stdout=subprocess.PIPE) 
  proc_stdout, proc_stderr = proc.communicate()
  proc.wait()

answered Apr 10 '13 at 10:49

Paul

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subprocess popen, how to get access?

1 Answers1