Useful code which uses reduce()?

Question

Does anyone here have any useful code which uses reduce() function in python? Is there any code other than the usual + and * that we see in the examples?

Refer Fate of reduce() in Python 3000 by GvR

Answer 1

The other uses I've found for it besides + and * were with and and or, but now we have any and all to replace those cases.

foldl and foldr do come up in Scheme a lot...

Here's some cute usages:

Flatten a list

Goal: turn [[1, 2, 3], [4, 5], [6, 7, 8]] into [1, 2, 3, 4, 5, 6, 7, 8].

reduce(list.__add__, [[1, 2, 3], [4, 5], [6, 7, 8]], [])

List of digits to a number

Goal: turn [1, 2, 3, 4, 5, 6, 7, 8] into 12345678.

Ugly, slow way:

int("".join(map(str, [1,2,3,4,5,6,7,8])))

Pretty reduce way:

reduce(lambda a,d: 10*a+d, [1,2,3,4,5,6,7,8], 0)

Answer 2

reduce() can be used to find Least common multiple for 3 or more numbers:

#!/usr/bin/env python
from math import gcd
from functools import reduce

def lcm(*args):
    return reduce(lambda a,b: a * b // gcd(a, b), args)

Example:

>>> lcm(100, 23, 98)
112700
>>> lcm(*range(1, 20))
232792560

Answer 3

reduce() could be used to resolve dotted names (where eval() is too unsafe to use):

>>> import __main__
>>> reduce(getattr, "os.path.abspath".split('.'), __main__)
<function abspath at 0x009AB530>

Answer 4

Find the intersection of N given lists:

input_list = [[1, 2, 3, 4, 5], [2, 3, 4, 5, 6], [3, 4, 5, 6, 7]]

result = reduce(set.intersection, map(set, input_list))

returns:

result = set([3, 4, 5])

via: Python - Intersection of two lists

Answer 5

I think reduce is a silly command. Hence:

reduce(lambda hold,next:hold+chr(((ord(next.upper())-65)+13)%26+65),'znlorabggbbhfrshy','')

Answer 6

Function composition: If you already have a list of functions that you'd like to apply in succession, such as:

color = lambda x: x.replace('brown', 'blue')
speed = lambda x: x.replace('quick', 'slow')
work = lambda x: x.replace('lazy', 'industrious')
fs = [str.lower, color, speed, work, str.title]

Then you can apply them all consecutively with:

>>> call = lambda s, func: func(s)
>>> s = "The Quick Brown Fox Jumps Over the Lazy Dog"
>>> reduce(call, fs, s)
'The Slow Blue Fox Jumps Over The Industrious Dog'

In this case, method chaining may be more readable. But sometimes it isn't possible, and this kind of composition may be more readable and maintainable than a f1(f2(f3(f4(x)))) kind of syntax.

Answer 7

The usage of reduce that I found in my code involved the situation where I had some class structure for logic expression and I needed to convert a list of these expression objects to a conjunction of the expressions. I already had a function make_and to create a conjunction given two expressions, so I wrote reduce(make_and,l). (I knew the list wasn't empty; otherwise it would have been something like reduce(make_and,l,make_true).)

This is exactly the reason that (some) functional programmers like reduce (or fold functions, as such functions are typically called). There are often already many binary functions like +, *, min, max, concatenation and, in my case, make_and and make_or. Having a reduce makes it trivial to lift these operations to lists (or trees or whatever you got, for fold functions in general).

Of course, if certain instantiations (such as sum) are often used, then you don't want to keep writing reduce. However, instead of defining the sum with some for-loop, you can just as easily define it with reduce.

Readability, as mentioned by others, is indeed an issue. You could argue, however, that only reason why people find reduce less "clear" is because it is not a function that many people know and/or use.

Answer 8

You could replace value = json_obj['a']['b']['c']['d']['e'] with:

value = reduce(dict.__getitem__, 'abcde', json_obj)

If you already have the path a/b/c/.. as a list. For example, Change values in dict of nested dicts using items in a list.

Answer 9

@Blair Conrad: You could also implement your glob/reduce using sum, like so:

files = sum([glob.glob(f) for f in args], [])

This is less verbose than either of your two examples, is perfectly Pythonic, and is still only one line of code.

So to answer the original question, I personally try to avoid using reduce because it's never really necessary and I find it to be less clear than other approaches. However, some people get used to reduce and come to prefer it to list comprehensions (especially Haskell programmers). But if you're not already thinking about a problem in terms of reduce, you probably don't need to worry about using it.

Answer 10

reduce can be used to support chained attribute lookups:

reduce(getattr, ('request', 'user', 'email'), self)

Of course, this is equivalent to

self.request.user.email

but it's useful when your code needs to accept an arbitrary list of attributes.

(Chained attributes of arbitrary length are common when dealing with Django models.)

Answer 11

reduce is useful when you need to find the union or intersection of a sequence of set-like objects.

>>> reduce(operator.or_, ({1}, {1, 2}, {1, 3}))  # union
{1, 2, 3}
>>> reduce(operator.and_, ({1}, {1, 2}, {1, 3}))  # intersection
{1}

(Apart from actual sets, an example of these are Django's Q objects.)

On the other hand, if you're dealing with bools, you should use any and all:

>>> any((True, False, True))
True

Answer 12

Reduce isn't limited to scalar operations; it can also be used to sort things into buckets. (This is what I use reduce for most often).

Imagine a case in which you have a list of objects, and you want to re-organize it hierarchically based on properties stored flatly in the object. In the following example, I produce a list of metadata objects related to articles in an XML-encoded newspaper with the articles function. articles generates a list of XML elements, and then maps through them one by one, producing objects that hold some interesting info about them. On the front end, I'm going to want to let the user browse the articles by section/subsection/headline. So I use reduce to take the list of articles and return a single dictionary that reflects the section/subsection/article hierarchy.

from lxml import etree
from Reader import Reader

class IssueReader(Reader):
    def articles(self):
        arts = self.q('//div3')  # inherited ... runs an xpath query against the issue
        subsection = etree.XPath('./ancestor::div2/@type')
        section = etree.XPath('./ancestor::div1/@type')
        header_text = etree.XPath('./head//text()')
        return map(lambda art: {
            'text_id': self.id,
            'path': self.getpath(art)[0],
            'subsection': (subsection(art)[0] or '[none]'),
            'section': (section(art)[0] or '[none]'),
            'headline': (''.join(header_text(art)) or '[none]')
        }, arts)

    def by_section(self):
        arts = self.articles()

        def extract(acc, art):  # acc for accumulator
            section = acc.get(art['section'], False)
            if section:
                subsection = acc.get(art['subsection'], False)
                if subsection:
                    subsection.append(art)
                else:
                    section[art['subsection']] = [art]
            else:
                acc[art['section']] = {art['subsection']: [art]}
            return acc

        return reduce(extract, arts, {})

I give both functions here because I think it shows how map and reduce can complement each other nicely when dealing with objects. The same thing could have been accomplished with a for loop, ... but spending some serious time with a functional language has tended to make me think in terms of map and reduce.

By the way, if anybody has a better way to set properties like I'm doing in extract, where the parents of the property you want to set might not exist yet, please let me know.

Answer 13

reduce can be used to get the list with the maximum nth element

reduce(lambda x,y: x if x[2] > y[2] else y,[[1,2,3,4],[5,2,5,7],[1,6,0,2]])

would return [5, 2, 5, 7] as it is the list with max 3rd element +

Answer 14

Not sure if this is what you are after but you can search source code on Google.

Follow the link for a search on 'function:reduce() lang:python' on Google Code search

At first glance the following projects use reduce()

• MoinMoin
• Zope
• Numeric
• ScientificPython

etc. etc. but then these are hardly surprising since they are huge projects.

The functionality of reduce can be done using function recursion which I guess Guido thought was more explicit.

Update:

Since Google's Code Search was discontinued on 15-Jan-2012, besides reverting to regular Google searches, there's something called Code Snippets Collection that looks promising. A number of other resources are mentioned in answers this (closed) question Replacement for Google Code Search?.

Update 2 (29-May-2017):

A good source for Python examples (in open-source code) is the Nullege search engine.

Answer 15

I'm writing a compose function for a language, so I construct the composed function using reduce along with my apply operator.

In a nutshell, compose takes a list of functions to compose into a single function. If I have a complex operation that is applied in stages, I want to put it all together like so:

complexop = compose(stage4, stage3, stage2, stage1)

This way, I can then apply it to an expression like so:

complexop(expression)

And I want it to be equivalent to:

stage4(stage3(stage2(stage1(expression))))

Now, to build my internal objects, I want it to say:

Lambda([Symbol('x')], Apply(stage4, Apply(stage3, Apply(stage2, Apply(stage1, Symbol('x'))))))

(The Lambda class builds a user-defined function, and Apply builds a function application.)

Now, reduce, unfortunately, folds the wrong way, so I wound up using, roughly:

reduce(lambda x,y: Apply(y, x), reversed(args + [Symbol('x')]))

To figure out what reduce produces, try these in the REPL:

reduce(lambda x, y: (x, y), range(1, 11))
reduce(lambda x, y: (y, x), reversed(range(1, 11)))

Answer 16

After grepping my code, it seems the only thing I've used reduce for is calculating the factorial:

reduce(operator.mul, xrange(1, x+1) or (1,))

Answer 17

import os

files = [
    # full filenames
    "var/log/apache/errors.log",
    "home/kane/images/avatars/crusader.png",
    "home/jane/documents/diary.txt",
    "home/kane/images/selfie.jpg",
    "var/log/abc.txt",
    "home/kane/.vimrc",
    "home/kane/images/avatars/paladin.png",
]

# unfolding of plain filiname list to file-tree
fs_tree = ({}, # dict of folders
           []) # list of files
for full_name in files:
    path, fn = os.path.split(full_name)
    reduce(
        # this fucction walks deep into path
        # and creates placeholders for subfolders
        lambda d, k: d[0].setdefault(k,         # walk deep
                                     ({}, [])), # or create subfolder storage
        path.split(os.path.sep),
        fs_tree
    )[1].append(fn)

print fs_tree
#({'home': (
#    {'jane': (
#        {'documents': (
#           {},
#           ['diary.txt']
#        )},
#        []
#    ),
#    'kane': (
#       {'images': (
#          {'avatars': (
#             {},
#             ['crusader.png',
#             'paladin.png']
#          )},
#          ['selfie.jpg']
#       )},
#       ['.vimrc']
#    )},
#    []
#  ),
#  'var': (
#     {'log': (
#         {'apache': (
#            {},
#            ['errors.log']
#         )},
#         ['abc.txt']
#     )},
#     [])
#},
#[])

Answer 18

I just found useful usage of reduce: splitting string without removing the delimiter. The code is entirely from Programatically Speaking blog. Here's the code:

reduce(lambda acc, elem: acc[:-1] + [acc[-1] + elem] if elem == "\n" else acc + [elem], re.split("(\n)", "a\nb\nc\n"), [])

Here's the result:

['a\n', 'b\n', 'c\n', '']

Note that it handles edge cases that popular answer in SO doesn't. For more in-depth explanation, I am redirecting you to original blog post.

Answer 19

I used reduce to concatenate a list of PostgreSQL search vectors with the || operator in sqlalchemy-searchable:

vectors = (self.column_vector(getattr(self.table.c, column_name))
           for column_name in self.indexed_columns)
concatenated = reduce(lambda x, y: x.op('||')(y), vectors)
compiled = concatenated.compile(self.conn)

Answer 20

I have an old Python implementation of pipegrep that uses reduce and the glob module to build a list of files to process:

files = []
files.extend(reduce(lambda x, y: x + y, map(glob.glob, args)))

I found it handy at the time, but it's really not necessary, as something similar is just as good, and probably more readable

files = []
for f in args:
    files.extend(glob.glob(f))

Answer 21

Let say that there are some yearly statistic data stored a list of Counters. We want to find the MIN/MAX values in each month across the different years. For example, for January it would be 10. And for February it would be 15. We need to store the results in a new Counter.

from collections import Counter

stat2011 = Counter({"January": 12, "February": 20, "March": 50, "April": 70, "May": 15,
           "June": 35, "July": 30, "August": 15, "September": 20, "October": 60,
           "November": 13, "December": 50})

stat2012 = Counter({"January": 36, "February": 15, "March": 50, "April": 10, "May": 90,
           "June": 25, "July": 35, "August": 15, "September": 20, "October": 30,
           "November": 10, "December": 25})

stat2013 = Counter({"January": 10, "February": 60, "March": 90, "April": 10, "May": 80,
           "June": 50, "July": 30, "August": 15, "September": 20, "October": 75,
           "November": 60, "December": 15})

stat_list = [stat2011, stat2012, stat2013]

print reduce(lambda x, y: x & y, stat_list)     # MIN
print reduce(lambda x, y: x | y, stat_list)     # MAX

Answer 22

I have objects representing some kind of overlapping intervals (genomic exons), and redefined their intersection using __and__:

class Exon:
    def __init__(self):
        ...
    def __and__(self,other):
        ...
        length = self.length + other.length  # (e.g.)
        return self.__class__(...length,...)

Then when I have a collection of them (for instance, in the same gene), I use

intersection = reduce(lambda x,y: x&y, exons)

Answer 23

def dump(fname,iterable):
  with open(fname,'w') as f:
    reduce(lambda x, y: f.write(unicode(y,'utf-8')), iterable)

Answer 24

Using reduce() to find out if a list of dates are consecutive:

from datetime import date, timedelta


def checked(d1, d2):
    """
    We assume the date list is sorted.
    If d2 & d1 are different by 1, everything up to d2 is consecutive, so d2
    can advance to the next reduction.
    If d2 & d1 are not different by 1, returning d1 - 1 for the next reduction
    will guarantee the result produced by reduce() to be something other than
    the last date in the sorted date list.

    Definition 1: 1/1/14, 1/2/14, 1/2/14, 1/3/14 is consider consecutive
    Definition 2: 1/1/14, 1/2/14, 1/2/14, 1/3/14 is consider not consecutive

    """
    #if (d2 - d1).days == 1 or (d2 - d1).days == 0:  # for Definition 1
    if (d2 - d1).days == 1:                          # for Definition 2
        return d2
    else:
        return d1 + timedelta(days=-1)

# datelist = [date(2014, 1, 1), date(2014, 1, 3),
#             date(2013, 12, 31), date(2013, 12, 30)]

# datelist = [date(2014, 2, 19), date(2014, 2, 19), date(2014, 2, 20),
#             date(2014, 2, 21), date(2014, 2, 22)]

datelist = [date(2014, 2, 19), date(2014, 2, 21),
            date(2014, 2, 22), date(2014, 2, 20)]

datelist.sort()

if datelist[-1] == reduce(checked, datelist):
    print "dates are consecutive"
else:
    print "dates are not consecutive"