Java string end with space

Question

always meet problem with java string's last end of string sign. It seems it occupy a space, therefore it may be return different answers when do if string[a] == string[b], or even sometimes a.equals(b) still doesn't work even a and b seems the same but one of them contain a end sign. Wonder Which function can be used for the ignoring feature of the string?

first trim the string then compare using equals , here == won't work — Senthil, Apr 15 '13 at 07:31
Rapprz I think C++ may count the same question so I tagged it. (I know now normally in C++ people always use char array instead of string) @juanchopanza yes, I did have the same problem with C++ before. — Lance, Apr 18 '13 at 15:55

score 4 · Accepted Answer · answered Apr 15 '13 at 07:31

Use String.trim() to remove surrounding whitespace and then use String.equals() (not ==, See 15.21 Equality Operators in the Java Language Specification for full details.). Remember that String instances are immutable so String.trim() returns a new String and it is that which must be used in the equals() check.

Note that trim() removes leading whitespace also. If this is undesired then use String.substring() to erase the trailing whitespace.

score 1 · Answer 2 · answered Apr 15 '13 at 07:31

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should always trim() the string before compare.

answered Apr 15 '13 at 07:31

Ankit

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why should we 'always' trim the string if comparing? – sabisabi Apr 15 '13 at 07:43
for any **meaningful** comparison, it would help reduce the bugs. – Ankit Apr 15 '13 at 07:45

score 0 · Answer 3 · answered Apr 15 '13 at 07:32

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trim()

will return your string without spaces in the start and ends.

Ex:

String s =" test ";
s =s.trim(); //will become "test"

answered Apr 15 '13 at 07:32

Suresh Atta

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score 0 · Answer 4 · answered Apr 15 '13 at 07:35

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you can use only stringA.equals(stringB); to remove white spaces use .trim()

answered Apr 15 '13 at 07:35

x3mik

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Java string end with space

4 Answers4