PHP - add 1 day to date format mm-dd-yyyy

Question

<?php
    $date = "04-15-2013";
    $date = strtotime($date);
    $date = strtotime("+1 day", $date);
    echo date('m-d-Y', $date);
?>

This is driving me crazy and seems so simple. I'm pretty new to PHP, but I can't figure this out. The echo returns 01-01-1970.

The $date will be coming from a POST in the format m-d-Y, I need to add one day and have it as a new variable to be used later.

Do I have to convert $date to Y-m-d, add 1 day, then convert back to m-d-Y? Would I be better off learning how to use DateTime?

If your date will be coming in from a `POST`, then you're probably better off using `$tomorrow = date('m-d-Y',strtotime("+1 days"));` (Fabio's answer) and `$tomorrow = $_POST[$tomorrow];` in your data collecting script. — Funk Forty Niner, Apr 15 '13 at 15:17

Fabio · Accepted Answer · 2013-04-15T15:14:01.737

130

there you go

$date = "04-15-2013";
$date1 = str_replace('-', '/', $date);
$tomorrow = date('m-d-Y',strtotime($date1 . "+1 days"));

echo $tomorrow;

this will output

04-16-2013

Documentation for both function
date
strtotime

edited Apr 15 '13 at 15:14

answered Apr 15 '13 at 15:08

Fabio

Perfect! I didn't know it would not recognize '-'. I have no problem changing it all over to '/'. Thank you! – Jayr Apr 15 '13 at 15:31

John Conde · Answer 2 · 2014-02-28T00:25:22.567

63

$date = DateTime::createFromFormat('m-d-Y', '04-15-2013');
$date->modify('+1 day');
echo $date->format('m-d-Y');

Or in PHP 5.4+

echo (DateTime::createFromFormat('m-d-Y', '04-15-2013'))->modify('+1 day')->format('m-d-Y');

reference

edited Feb 28 '14 at 00:25

answered Apr 15 '13 at 15:10

John Conde

score 17 · Answer 3 · answered Dec 12 '16 at 14:33

17

$date = strtotime("+1 day");
echo date('m-d-y',$date);

answered Dec 12 '16 at 14:33

insoftservice

score 3 · Answer 4 · answered Apr 15 '13 at 15:11

3

$date = date_create('2000-01-01');
date_add($date, date_interval_create_from_date_string('1 days'));
echo date_format($date, 'Y-m-d');

output

2000-01-2

answered Apr 15 '13 at 15:11

score 1 · Answer 5 · answered Apr 15 '13 at 15:10

1

The format you've used is not recognized by strtotime(). Replace

$date = "04-15-2013";

by

$date = "04/15/2013";

Or if you want to use - then use the following line with the year in front:

$date = "2013-04-15";

answered Apr 15 '13 at 15:10

hek2mgl

score 1 · Answer 6 · edited Jun 20 '20 at 09:12

Actually I wanted same alike thing, To get one year backward date, for a given date! :-)

With the hint of above answer from @mohammad mohsenipur I got to the following link, via his given link!

Luckily, there is a method same as date_add method, named date_sub method! :-) I do the following to get done what I wanted!

$date = date_create('2000-01-01');
date_sub($date, date_interval_create_from_date_string('1 years'));
echo date_format($date, 'Y-m-d');

Hopes this answer will help somebody too! :-)

Good luck guys!

6 Answers6