How to display value in second text box by entering value in first for some condition

Question

greeting to all, is there any way to get value in second text box, i have some filed as shown in my image, enter image description here if we type 90 in result text box then automaticaly the value of nor/ab field should be "Low", for 180 should be high. so we have to check over condition for 110-170(range field)...

actualy i am puzzled for the value of range field in the form of 110-170.... Any idea will be appreciated....thanks in advance...

Here you go; http://stackoverflow.com/questions/1280499/jquery-set-select-index. `if (result.value < 90) { /* Do link-code here, with low */ } else if (result.value > 180) { /* Do link-code here, with high */ } else { Do link-code here, with normal }` — , Apr 17 '13 at 11:30

score 1 · Accepted Answer · answered Apr 17 '13 at 11:55

Try to do this way:

var result = $('#result');
var sel = $('#select');

result.on('keydown keyup', function () {
   if (result.val() < 90) {
      $('option[value="low"]', sel).prop('selected', true);
    } else if (result.val() > 90) {
      $('option[value="high"]', sel).prop('selected', true);
    }
});

Demo Fiddle

score 0 · Answer 2 · answered Apr 17 '13 at 11:34

0

var result = $("#result").val();
if(result >= 110 || result <=170){
 $("#nor").val('Normal');
}
else if(result == 90){
  $("#nor").val('Low');
}
else if(result == 180){
  $("#nor").val('High');
}

answered Apr 17 '13 at 11:34

웃웃웃웃웃

11,829
15
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91

sir i do not have only 110-170 value for range field...these are coming from database for specific test...so i have to fix some condition on result field for range field but range field are in the form like 110-170..so i am confused..... – Dinesh Apr 17 '13 at 11:39
@Jack for that you can add else condition at last of above answer that will show high if it goes above 180 – Sangna Jani Apr 17 '13 at 11:47

score 0 · Answer 3 · answered Apr 17 '13 at 11:38

0

Assuming your row is wrapped in a parent div:

$('.result').change(function(){
    level = (($(this).val() < 170) ? 'low' : 'high');
    $(this).parent().find('.nor').val(level);
}

answered Apr 17 '13 at 11:38

skndstry

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1
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sir i do not have only 110-170 value for range field...these are coming from database for specific test...so i have to fix some condition on result field for range field but range field are in the form like 110-170..so i am confused – Dinesh Apr 17 '13 at 11:41

score 0 · Answer 4 · answered Apr 17 '13 at 11:40

It can be improved to be a bit more readable if needed, but it should do the trick:

$("#result").on('keyup',function(){
    if($(this).val()<110){
    $("#select").val("low");
    }
    else if($(this).val()<=170){
        $("#select").val("normal");
    }
    else{
            $("#select").val("high");
    }
})

http://jsfiddle.net/YWUrR/

How to display value in second text box by entering value in first for some condition

4 Answers4

Demo Fiddle