Unable to find matching navigation case with from-view-id

Question

i have a controller and in this controller i get some results from the db

This is the function which i get results

 public DataModel getFts() {

        this.session = HibernateUtil.getSessionFactory().getCurrentSession();

        List<FinancialTransactions> ftList = null;
        try {
            org.hibernate.Transaction tx = session.beginTransaction();
            Query q = session.createQuery("from FinancialTransactions where Date='" + beginDate + "'");
            ftList = (List<FinancialTransactions>) q.list();
        } catch (Exception e) {
            e.printStackTrace();
        }

        return ftDataModel = new ListDataModel(ftList);
    }

This controllers name is ftController

in jsf

   <h:form styleClass="jsfcrud_list_form">
                <h:dataTable value="#{ftController.ftDataModel}" var="item" border="0" cellpadding="2" cellspacing="0" rowClasses="jsfcrud_odd_row,jsfcrud_even_row" rules="all" style="border:solid 1px">
                    <h:column>
                        <f:facet name="header">
                            <h:outputText value="Title"/>
                        </f:facet>
                        <h:outputText value="#{item.id}"/>
                    </h:column>
                </h:dataTable>
                <br/>
                 <h:commandButton type="submit" action="#{ftController. getFts()}"  id="searchButton"  value="Search"  />
            </h:form>

i have above code. This jsf's name is financialTransactions but it gives below error:

Unable to find matching navigation case with from-view-id '/financialTransactions.xhtml' for action '#{ftController. getFts()}' with outcome 'javax.faces.model.ListDataModel@32ee7cee'

What's wrong?

Aritz · Answer 1 · 2013-04-17T20:29:24.283

Basically, JSF expects a navigation result as the method return. You have to differ in JSF between getters and action methods.

A getter returns something to display in the page you're actually rendering.
An action method can perform some action in your bean and return a
navigation result as an String, or a void or empty String if you want to keep the current page.

You're calling a getter method as an action method and JSF expects you will return a navigation result, however it finds a javax.faces.model.ListDataModel Object.

See more about implicit navigation in JSF 2.

It looks that what you want is to load a list taking search parameters into account. Then what you can do is to call a real action method:

<h:commandButton value="Search" action="#{ftController.loadFts}" />

Where loadFts method will load the search results in your list.

score 0 · Answer 2 · edited Jul 05 '14 at 09:15

In action attribute of commandButton, a return navigation string is expected, which may be a logical outcome string OR an implicit navigation string (Directly the name of the next page you want to navigate to). But here your action method is returning a DataModel object whose toString() doesn't make any sense for the navigation model of JSF. Give the name of the JSF file there to which you want to navigate to.

Unable to find matching navigation case with from-view-id

2 Answers2