Accepting multiple arguments through sh script [UNIX]

Question

What I'm trying to do here is allow users to enter multiple arguments (filenames) and send them to a recycle bin I have created the sh script is called "sh safe_rm"

so I would do this:

$] sh safe_rm testFile2 testFile 3

I need both files able to be passed, any ideas?

file=$1

if [ $# -eq 0 ]
then
   echo "You have not entered a file"
   exit
elif [ -d $file ]
then
   echo "Your file is a directory"
   exit
elif [ -e $file ]
then
   sendToBin
else
   echo "Your file $file does not exist"
   exit


  fi

You'll want to look into this: http://stackoverflow.com/questions/255898/how-to-iterate-over-arguments-in-bash-script — Øyvind Robertsen, Apr 17 '13 at 17:58

score 2 · Answer 1 · edited May 23 '17 at 12:25

2

Try something like this:

sh safe_rm testFile2 testFile 3

for var in "$@"
do
    echo "$var"
done

This will print:

testFile2
testFile
3

See this post for more info

edited May 23 '17 at 12:25

Community

1
1

answered Apr 17 '13 at 17:59

1337holiday

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+1. @claybanks, note the necessary use of double quotes everywhere. – glenn jackman May 14 '14 at 20:29

Accepting multiple arguments through sh script [UNIX]

1 Answers1