How to make a post call to a Web Api Action?

Question

I've created a Web API Action as below

[HttpPost]
public void Load(string siteName, string providerName, UserDetails userDetails)
{
// implementation
}

The route I've registered for this is as below (not sure if it's correct?):

 config.Routes.MapHttpRoute(
             name: "loadUserDetails",
             routeTemplate: "sites/{siteName}/User/Load/{providerName}/{userDetailsList}",
             defaults: new
             {
                 controller = "User",
                 action = "Load",
                 providerName = UrlParameter.Optional
             });

The providerName parameter should be optional and I'm using Xml Serialization.

The action should response to the below url sample:

http://www.domain.com/sites/site1/user/load/provider1/[some user details in the post]
or
http://www.domain.com/sites/site1/user/load/[some user details in the post]

How could I make a post call to this action so that I can test my service?

yes, but it can be set later; the post won't call this action like a c# class. the default provider is loaded from the web.config later. — The Light, Apr 18 '13 at 15:38

score 3 · Answer 1 · edited May 23 '17 at 11:51

3

From: HTTP request with post

HttpWebRequest request =
    (HttpWebRequest)WebRequest.Create(@"http:\\domain.com\page.asp");

ASCIIEncoding encoding = new ASCIIEncoding();
string postData = "username=user";
postData += "&password=pass";
byte[] data = encoding.GetBytes(postData);

request.Method = "POST";
request.ContentType = "application/x-www-form-urlencoded";
request.ContentLength = data.Length;

using (Stream stream = request.GetRequestStream())
{
    stream.Write(data,0,data.Length);
}

HttpWebResponse response = (HttpWebResponse)request.GetResponse();

string responseString = new StreamReader(response.GetResponseStream()).ReadToEnd();

edited May 23 '17 at 11:51

Community

1
1

answered Apr 18 '13 at 15:27

Wesley Schleumer de Góes

6,347
2
19
27

the original postdata you're sending, shouldn't it be in the xml format? also if I have another UserDetails userDetails input parameter how does it know to which parameter it should be assigning it to?! – The Light Apr 19 '13 at 08:01
How would you send a more complex xml data? – The Light Apr 22 '13 at 07:33
Are you trying to make an raw post? – Wesley Schleumer de Góes Apr 22 '13 at 14:11

score 0 · Answer 2 · answered Apr 18 '13 at 15:26

0

If your question is how to test your action, you can use Fidler.

See http://www.mehdi-khalili.com/fiddler-in-action/part-2

answered Apr 18 '13 at 15:26

Sam Leach

12,746
9
45
73

score 0 · Answer 3 · answered Apr 19 '13 at 09:22

0

See the response from here using RestSharp and Web Request:

http://pooyakhamooshi.blogspot.co.uk/2013/04/how-to-post-request-to-web-api-web.html

answered Apr 19 '13 at 09:22

The Light

26,341
62
176
258

How to make a post call to a Web Api Action?

3 Answers3

Linked