How do I pass a variable to the layout using Laravel' Blade templating?

Question

In Laravel 4, my controller uses a Blade layout:

class PagesController extends BaseController {
    protected $layout = 'layouts.master';
}

The master layout has outputs the variable title and then displays a view:

...
<title>{{ $title }}</title>
...
@yield('content')
....

However, in my controller I only appear to be able to pass variables to the subview, not the layout. For example, an action could be:

public function index()
{
    $this->layout->content = View::make('pages/index', array('title' => 'Home page'));
}

This will only pass the $title variable to the content section of the view. How can I provide that variable to the whole view, or at the very least the master layout?

s3v3n · Accepted Answer · 2022-01-31T20:26:45.750

256

If you're using @extends in your content layout you can use this:

@extends('master', ['title' => $title])

Note that same as above works with children, like:

@include('views.subView', ['my_variable' => 'my-value'])

Usage

Then where variable is passed to, use it like:

<title>{{ $title ?? 'Default Title' }}</title>

edited Jan 31 '22 at 20:26

answered Mar 29 '15 at 21:38

s3v3n

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2

It took me a lot of googling to find this! It is just this syntax that you got to get perfect and docs don't show all these subtleties. I mean this is what official docs say `@component('alert', ['foo' => 'bar'])`...... – Arthur Tarasov Jan 18 '18 at 08:28
I am doing this and I am getting an undefined error on the layout page. Any ideas? – LucyTurtle Mar 15 '18 at 00:12
@LucyTurtle see usage section (provide default value, like: `{{ $title ?? 'My Default Title' }}`) – Top-Master Jan 05 '22 at 15:12

score 51 · Answer 2 · answered Jun 13 '16 at 12:55

51

For future Google'rs that use Laravel 5, you can now also use it with includes,

@include('views.otherView', ['variable' => 1])

answered Jun 13 '16 at 12:55

Chilion

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this is what im looking for to finally create a component based application on laravel, thanks! – Ron Michael Jul 10 '18 at 10:33
if I only pass ["one"], how do I get it in the template? – Javier J Solis Flores Aug 04 '19 at 18:55

Rohan Krishna · Answer 3 · 2015-05-25T16:24:17.553

23

In the Blade Template : define a variable like this

@extends('app',['title' => 'Your Title Goes Here'])
@section('content')

And in the app.blade.php or any other of your choice ( I'm just following default Laravel 5 setup )

<title>{{ $title or 'Default title Information if not set explicitly' }}</title>

This is my first answer here. Hope it works.Good luck!

edited May 25 '15 at 16:24

answered May 24 '15 at 15:55

Rohan Krishna

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This helped me save few hours..! Used it in Laravel 5.4 and it works great.. Thanks for the answer... – Saiyan Prince Aug 05 '17 at 06:04
3

I had to do: `{{ $title ?? 'Default Title' }}` – Damien Jan 10 '18 at 14:29

score 19 · Answer 4 · answered Jun 10 '13 at 07:10

19

I was able to solve that problem by adding this to my controller method:

    $title = 'My Title Here';
    View::share('title', $title);

$this->layout->title = 'Home page'; did not work either.

answered Jun 10 '13 at 07:10

Timothy

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This worked for me in laravel 5.1. Easiest way to solve the problem. – chuysbz Oct 30 '15 at 18:41

score 5 · Answer 5 · answered May 13 '16 at 07:25

5

Simplest way to solve:

view()->share('title', 'My Title Here');

Or using view Facade:

use View;

...

View::share('title', 'My Title Here');

answered May 13 '16 at 07:25

Efra

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4

can i execute it in a route middleware? – mukade Feb 21 '18 at 02:11

score 4 · Answer 6 · edited Apr 22 '13 at 12:45

4

It appears as though I can pass variables to the entire layout using attributes on the layout object, for example to solve my problem I was able to do the following:

$this->layout->title = 'Home page';

edited Apr 22 '13 at 12:45

JackPoint

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answered Apr 20 '13 at 08:04

Dwight

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This didn't work for me. I currently get an error stating that it does not exist as a variable. – Adam Libonatti-Roche Apr 24 '13 at 20:35
where can I find the layout object? – Yevgeniy Afanasyev Oct 24 '18 at 21:42

score 1 · Answer 7 · edited Oct 25 '18 at 03:53

1

class PagesController extends BaseController {
    protected $layout = 'layouts.master';

    public function index()
    {
        $this->layout->title = "Home page";
        $this->layout->content = View::make('pages/index');
    }
}

At the Blade Template file, REMEMBER to use @ in front the variable.

...
<title>{{ $title or '' }}</title>
...
@yield('content')
...

edited Oct 25 '18 at 03:53

Yevgeniy Afanasyev

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answered Apr 07 '14 at 14:30

Shiro

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@YevgeniyAfanasyev, this question you should ask back post owner. I just refer back his coding. Kind of weird you ask back me.... And this was answered in 2014. Of course I was referring on the version he asking which is Laravel 4. – Shiro Oct 25 '18 at 00:44

score 1 · Answer 8 · answered Oct 19 '19 at 07:34

1

just try this simple method: in controller:-

 public function index()
   {
        $data = array(
            'title' => 'Home',
            'otherData' => 'Data Here'
        );
        return view('front.landing')->with($data);
   }

And in you layout (app.blade.php) :

<title>{{ $title }} - {{ config('app.name') }} </title>

Thats all.

answered Oct 19 '19 at 07:34

Web Decode

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Could you explain how this solves the problem? And what new does it contribute over and above the previous (especially accepted) answers? – gstukelj Oct 19 '19 at 07:46
Welcome to SO! When you place an answer, even if it is ok, you should explain it a little bit, and in your case, as there are one similar, try to explain the pros and cons of your answer. – David García Bodego Oct 19 '19 at 07:58

score 1 · Answer 9 · answered Aug 30 '20 at 17:48

1

if you want to get the variables of sections you can pay like this:

$_view      = new \View;
$_sections  = $_view->getFacadeRoot()->getSections();
dd($_sections);
/*
Out:
array:1 [▼
  "title" => "Painel"
]
*/

answered Aug 30 '20 at 17:48

DEV Tiago França

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Kunal Rajput · Answer 10 · 2022-11-25T10:16:19.973

1

Following is simple solution worked for me.

In layout

    <title>@yield('Page-Title') </title>

In your blade file 

@section('Page-Title')
My Page Title
@endsection

edited Nov 25 '22 at 10:16

answered Jun 29 '21 at 12:37

Kunal Rajput

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It works with me on laravel 8 based project, thank you very much – Hassan Ashraf Oct 11 '22 at 20:27

score -1 · Answer 11 · answered Aug 02 '13 at 08:00

-1

You can try:

public function index()
{
    return View::make('pages/index', array('title' => 'Home page'));
}

answered Aug 02 '13 at 08:00

Melvin

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score -2 · Answer 12 · answered Aug 02 '13 at 04:28

$data['title'] = $this->layout->title = 'The Home Page';
$this->layout->content = View::make('home', $data);

I've done this so far because I needed in both the view and master file. It seems if you don't use $this->layout->title it won't be available in the master layout. Improvements welcome!

How do I pass a variable to the layout using Laravel' Blade templating?

12 Answers12

Usage

Linked