Retrieving date from sequence does not give the value

Question

I'm trying to run the following code in R

> mySeq <-  seq(as.Date("2012-1-1",format = "%Y-%m-%d"),
          as.Date("2012-1-3",format = "%Y-%m-%d"),
          by="1 day")

> for (i in mySeq){print(i)}

And I get:

[1] 15340
[1] 15341
[1] 15342

but mySeq[1] returns "2012-01-01"

Why? what am I missing here?

if you add `as.Date(i)` will give you what you want. `for (i in mySeq){print(as.Date(i))}` — Jilber Urbina, Apr 22 '13 at 13:05
Actually your solution did not work for me. I get: for (i in mySeq){print(as.Date(i))} Error in as.Date.numeric(i) : 'origin' must be supplied" — Ika, Apr 22 '13 at 13:12

score 4 · Accepted Answer · answered Apr 22 '13 at 13:05

4

Your date values are converted to numeric in for() function to use them as index values.

Instead you can use seq_along() to get index values and then print mySeq[i].

for(i in seq_along(mySeq)) {print(mySeq[i])}

answered Apr 22 '13 at 13:05

Didzis Elferts

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+1 I was already putting this down as an answer, but you where faster :) – Paul Hiemstra Apr 22 '13 at 13:05
@PaulHiemstra it doesn't happen too often, usually I'm the one who have to discard my answer as it is already answered. – Didzis Elferts Apr 22 '13 at 13:07
+1 for identifying the coercion to numeric. – João Daniel Apr 22 '13 at 13:11
Alternatively, use `for (i in as.list(mySeq)) {print(i)}`. If you'll need `i` more than once in the body of the `for` loop, this is easier than typing `mySeq[i]` every time. – Alexander Hanysz Jan 20 '14 at 00:15

Retrieving date from sequence does not give the value

1 Answers1