guys,i have a problem on using xinetd,the error message is 'xinetd[20126]: execv( /home/fulu/download/mysqlchk_status2.sh ) failed: Exec format error (errno = 8)'
- the system operation is : CentOS release 6.2;
- i installed the xinetd by the command 'sudo yum install xinetd'
- i edited the /etc/services, add my port 6033 for my service named 'mysqlchk'
the service 'mysqlchk' in /etc/xinetd.d/mysqlchk is
service mysqlchk { disable = no flags = REUSE socket_type = stream port = 6033 wait = no user = fulu server = /home/fulu/download/mysqlchk_status2.sh log_on_failure += USERID }
the shell file /home/fulu/download/mysqlchk_status2.sh content is
echo 'test'
6.i can run the command /home/fulu/download/mysqlchk_status2.sh straightly and get the result 'test'
when i telnet 127.0.0.1 6033,i get the output
Trying 127.0.0.1... Connected to 127.0.0.1. Escape character is '^]'. Connection closed by foreign host.
then i tail the log file /var/log/messages,it shows
Apr 22 22:01:47 AY1304111122016 xinetd[20001]: START: mysqlchk pid=20126 from=127.0.0.1
Apr 22 22:01:47 AY1304111122016 xinetd[20126]: execv( /home/fulu/download/mysqlchk_status2.sh ) failed: Exec format error (errno = 8)
Apr 22 22:01:47 AY1304111122016 xinetd[20001]: EXIT: mysqlchk status=0 pid=20126 duration=0(sec)
i don't know why,can anybody help me ?