How to find out a php file is included or accessed directly?

Question

Is there any way to find out if a php script is accessed directly or it's included.

Suppose we don't where it's included, so setting session variable won't solve the problem. I can not check where it's included. it may be more than 20 places!
It should be detected in php script. (via php functions and variables)

possible duplicate of http://stackoverflow.com/questions/2397004/php-check-if-a-file-is-loaded-directly-instead-of-including — Alex Shesterov, Apr 22 '13 at 18:18
[List your includes](http://php.net/manual/en/function.get-included-files.php) and [Prevent Direct Access](http://stackoverflow.com/questions/409496/prevent-direct-access-to-a-php-include-file) — Unexpected Pair of Colons, Apr 22 '13 at 18:18
no it's not duplicate, see point 1 of my question, I can not check where it's included. it may be more than 20 places! — hpaknia, Apr 22 '13 at 18:24

score 16 · Accepted Answer · answered Apr 22 '13 at 18:17

16

if(__FILE__ != $_SERVER['SCRIPT_FILENAME']) {
  // we're in an include
}

answered Apr 22 '13 at 18:17

ceejayoz

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score 3 · Answer 2 · answered Apr 27 '14 at 02:07

Used ceejayoz's answer but I have troubles when using symlinked files and paths due to __FILE__ being resolved to the real path automatically. So I used realpath() function on $_SERVER['SCRIPT_FILENAME'] instead to resolve both paths to the real path to solve the problem.

if(__FILE__ != realpath($_SERVER['SCRIPT_FILENAME'])) {
    // we're in an include
}

How to find out a php file is included or accessed directly?

2 Answers2

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