Print in Java Char array as binary

Question

I've a char array

static char[] myArray  ={   
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0xf8, 0x48, 0x48, 0x48, 0xb0, 0x00, 0xc0, 0x20,
0x20, 0x20, 0xc0, 0x00, 0xc0, 0x20, 0x20, 0x20, 0xc0, 0x00, 0x40, 0xa0, 0xa0, 0xa0, 0x20, 0x00,
0x00, 0x20, 0xf0, 0x20, 0x20, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x08, 0x08, 0xf8, 0x08,
};

How could I print it as 8-bit binary ?

Take a look at: http://stackoverflow.com/questions/917163/convert-a-string-like-testing123-to-binary-in-java — prashant, Apr 23 '13 at 07:44
printing a single char: http://stackoverflow.com/questions/6381504/how-do-i-print-the-binary-representation-of-the-first-character-in-a-string Adding the loop is straightforward. — Vincent van der Weele, Apr 23 '13 at 07:44
It's not as same as those links, the conversion to binary is the same, but the _8-bit_ part is not. — masoud, Apr 23 '13 at 08:17

masoud · Accepted Answer · 2013-04-23T07:51:22.490

Use toBinaryString for each item:

for (int i = 0; i < myArray.length; i++) {
        String b = Integer.toBinaryString(myArray[i]);

        if (b.length() < 8) {
            b = "000000000".substring(0, 8 - b.length()).concat(b);
        } else {
            b = b.substring(b.length() - 8);
        }

        System.out.print(b + " ");
 }

Output

00000000 00000000 00000000 00000000 00000000 00000000 00000000 00000000 11111000 01001000 01001000 01001000 1011000 ...

score 0 · Answer 2 · answered Apr 23 '13 at 07:46

0

if you output to be 0000000000000000f848484... then

    for(char c : myArray) {
        System.out.printf("%02x", (int)c);
    }

answered Apr 23 '13 at 07:46

Evgeniy Dorofeev

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1

This does not output binary ;) – Matthieu Riegler Apr 23 '13 at 07:59

Print in Java Char array as binary

2 Answers2