Javascript regex: make different spaces depending on lenght: 1 000, 10 000, 100 000

Question

So, I have this string, which can contain a number of any length really.

I need a regex which makes the strings like this:

For 100000, I have made this: /.{1,3}/g, but that only works from 100 000 and up. Is this possible?

@kjelelokk Can you please search on google before asking questions here? Please — Andreas Louv, Apr 24 '13 at 13:56
@NULL I did, guess I have poor Google skills. Also didn't know they were called thousand separators, English isn't my first language. Sorry. — ptf, Apr 24 '13 at 14:07

score 6 · Accepted Answer · answered Apr 24 '13 at 13:53

6

So basically you want thousand separators.

Look into number_format on PHPJS, or use this simplified version:

var num = 10000;
alert((""+num).replace(/\B(?=(?:\d{3})+(?!\d))/g," ")) // 10 000

answered Apr 24 '13 at 13:53

Niet the Dark Absol

320,036
81
464
592

If `num` have more than 3 decimals the result will look something like this: `var num=1234.5678` => `1 234.5 678` – Andreas Louv Apr 24 '13 at 16:55

score 0 · Answer 2 · answered Apr 24 '13 at 13:53

You can take a look at the code on phpjs.

He's created a Javascript function to mimic php's number_format().

This is copy/paste and I stripped comments:

function number_format (number, decimals, dec_point, thousands_sep) {
  number = (number + '').replace(/[^0-9+\-Ee.]/g, '');
  var n = !isFinite(+number) ? 0 : +number,
    prec = !isFinite(+decimals) ? 0 : Math.abs(decimals),
    sep = (typeof thousands_sep === 'undefined') ? ',' : thousands_sep,
    dec = (typeof dec_point === 'undefined') ? '.' : dec_point,
    s = '',
    toFixedFix = function (n, prec) {
      var k = Math.pow(10, prec);
      return '' + Math.round(n * k) / k;
    };
  // Fix for IE parseFloat(0.55).toFixed(0) = 0;
  s = (prec ? toFixedFix(n, prec) : '' + Math.round(n)).split('.');
  if (s[0].length > 3) {
    s[0] = s[0].replace(/\B(?=(?:\d{3})+(?!\d))/g, sep);
  }
  if ((s[1] || '').length < prec) {
    s[1] = s[1] || '';
    s[1] += new Array(prec - s[1].length + 1).join('0');
  }
  return s.join(dec);
}

I take no credit for this code.

Really shouldn't +1 that but had to. :P Made me giggle and it's been a long day trying to learn Ada. — Glitch Desire, Apr 24 '13 at 13:55

Javascript regex: make different spaces depending on lenght: 1 000, 10 000, 100 000

2 Answers2