Similar topic is already discussed in the forum. But I have some different problem in following code:
double total;
cin >> total;
cout << fixed << setprecision(2) << total;
If I give input as 100.00 then program prints just 100 but not 100.00
How can I print 100.00?
cout << fixed << setprecision(2) << total;
setprecision specifies the minimum precision. So
cout << setprecision (2) << 1.2;
will print 1.2
fixed says that there will be a fixed number of decimal digits after the decimal point
cout << setprecision (2) << fixed << 1.2;
will print 1.20
It is possible to print a 15 decimal number in C++ using the following:
#include <iomanip>
#include <iostream>
cout << fixed << setprecision(15) << " The Real_Pi is: " << real_pi << endl;
cout << fixed << setprecision(15) << " My Result_Pi is: " << my_pi << endl;
cout << fixed << setprecision(15) << " Processing error is: " << Error_of_Computing << endl;
cout << fixed << setprecision(15) << " Processing time is: " << End_Time-Start_Time << endl;
_getch();
return 0;
The easiest way to do this, is using cstdio's printf. Actually, i'm surprised that anyone mentioned printf! anyway, you need to include the library, like this...
#include<cstdio>
int main() {
double total;
cin>>total;
printf("%.2f\n", total);
}
This will print the value of "total" (that's what %, and then ,total does) with 2 floating points (that's what .2f does). And the \n at the end, is just the end of line, and this works with UVa's judge online compiler options, that is:
g++ -lm -lcrypt -O2 -pipe -DONLINE_JUDGE filename.cpp
the code you are trying to run will not run with this compiler options...
Using header file stdio.h you can easily do it as usual like c. before using %.2lf(set a specific number after % specifier.) using printf().
It simply printf specific digits after decimal point.
#include <stdio.h>
#include <iostream>
using namespace std;
int main()
{
double total=100;
printf("%.2lf",total);//this prints 100.00 like as C
}
This will be possible with setiosflags(ios::showpoint).
