How can I get filename of current working cs file and the name of the current class

Question

Suppose I am working on Welcome.cs file. In the constructor I want to print "Welcome". However, If I put the same code in HelloWorld.cs, it should print HellowWorld. How do I do that?

Code files have no influence on your compiled application. You can have an application with 10.000 classes in one codefile. — Carsten, Apr 30 '13 at 08:28
Do you want the name of the **file** or the **class**? They are fundamentally different and anything they have in common is only by convention. — J. Steen, Apr 30 '13 at 08:29
@TimSchmelter there are Framework methods for doing this now, so I think it's ok to keep this question — illegal-immigrant, Apr 30 '13 at 08:43

score 14 · Answer 1 · answered Apr 30 '13 at 08:29

14

You can try

string thisFile = new System.Diagnostics.StackTrace(true).GetFrame(0).GetFileName();

answered Apr 30 '13 at 08:29

Schaemelhout

685
9
25

2

This is the way to do it. Note that the `true` means include debug information. This only works on a debug build, which emits the `pdb` file containing source information. – harpo Apr 30 '13 at 08:30
1

This is the way to do it if OP hadn't been confused. =) – J. Steen Apr 30 '13 at 08:32
@harpo So this wouldn't work in production build? – Andrew Jul 04 '19 at 18:40

score 11 · Answer 2 · answered Apr 30 '13 at 08:28

11

if I've understood correctly, try this.GetType().Name

answered Apr 30 '13 at 08:28

NDJ

5,189
1
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1

One of us hasn't understood correctly. The OP asked how to get the source file name. – harpo Apr 30 '13 at 08:29
@harpo - just read his comment - seems he did mean class – NDJ Apr 30 '13 at 08:32
Yes I mean the class name. I got the answer. Thanx buddy – user2039445 Apr 30 '13 at 08:33

illegal-immigrant · Answer 3 · 2013-04-30T08:49:13.463

How to print

[current file name - method name - line number] ?

private static void Log(string text,
                        [CallerFilePath] string file = "",
                        [CallerMemberName] string member = "",
                        [CallerLineNumber] int line = 0)
{
    Console.WriteLine("{0}_{1}({2}): {3}", Path.GetFileName(file), member, line, text);
}

Test:

Log("Test");

Output:

Program.cs_Main(11): Test

score 8 · Answer 4 · answered Apr 30 '13 at 08:29

8

Try this to get the file name:

string currentFile = new System.Diagnostics.StackTrace(true).GetFrame(0).GetFileName();

To get the current line:

int currentLine = new System.Diagnostics.StackTrace(true).GetFrame(0).GetFileLineNumber();

answered Apr 30 '13 at 08:29

Carlos Landeras

11,025
11
56
82

score 0 · Answer 5 · answered Apr 30 '13 at 08:36

0

If you want to get the class name, you can use Reflection technique.

eg:

Type classType = yourObject.GetType();

you can get the name of the class from

classType.Name

answered Apr 30 '13 at 08:36

Arun

3,478
8
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46

Great answer, but unfortunately this answer is already present. – user2039445 Apr 30 '13 at 08:37

How can I get filename of current working cs file and the name of the current class

5 Answers5

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