find the number of every letters in a word

Question

User will enter a String, For instance if the user enters YYYCZZZZGG: Program will evaluate the frequency of characters in the string. For YYYCZZZZGG string, C is seen only for 1, G is repeated 2, Y has a frequency of 3, and Z’s frequency is 4.

after finding number of each letter how can I draw a bar graph using the numbers of the programs output?

*"User will enter a String, .. Program will evaluate the frequency"* Programmer will show some effort.. — Andrew Thompson, Apr 30 '13 at 09:07
If you are okay with order N solution just go through all the letters then create a map M like M['C']=M['C']+1 for each occurance and then iterate over the map. — specialscope, Apr 30 '13 at 09:11

score 1 · Answer 1 · answered Apr 30 '13 at 09:11

1

Use Apache StringUtils:

It contains a method that can be used like StringUtils.countMatches("YYYCZZZZGG", "Y");

answered Apr 30 '13 at 09:11

Vineet Singla

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score 0 · Answer 2 · edited May 23 '17 at 12:21

0

int count = StringUtils.countMatches("YYYCZZZZGG", "C");

Just a matter of copy paste from Java: How do I count the number of occurrences of a char in a String?

edited May 23 '17 at 12:21

Community

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answered Apr 30 '13 at 09:09

Toon Casteele

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These: http://commons.apache.org/proper/commons-lang/javadocs/api-2.6/org/apache/commons/lang/StringUtils.html – Toon Casteele Apr 30 '13 at 09:12

score 0 · Answer 3 · edited Apr 30 '13 at 09:31

    String str="YYYCZZZZGG";
    Map<Character,Integer> map=new HashMap<Character,Integer>();

    for (char c : str.toCharArray()) {
        if(map.containsKey(c))
        {
            int i=map.get(c);
            i++;
            map.put(c, i);
        }
        else
        {
            map.put(c, 0);
        }
    }

    for(Map.Entry<Character, Integer> entry:map.entrySet())
    {
        char c=entry.getKey();
        int  count=entry.getValue();
    }

score 0 · Answer 4 · answered Apr 30 '13 at 09:11

You can do it like this:

 String s = "YYYCZZZZGG";
 Map<Character, Float> m = new TreeMap<Character, Float>();
 for (char c : s.toCharArray()) {
     if (m.containsKey(c))
            m.put(c, m.get(c) + 1);
        else
            m.put(c, 1f);
 }

 for (char c : s.toCharArray()) {
      float freq = m.get(c) / s.length();
      System.out.println(c + " " + freq);
  }

Or you can use StringUtils class like:

System.out.println("The occurrence of Z is "+StringUtils.countMatches(s, "C"));

score 0 · Accepted Answer · answered Apr 30 '13 at 09:15

Try this:

public static void main(String[] args) {
    String input = "YYYCZZZZGG";
    Map<Character, Integer> map = new HashMap<Character, Integer>(); // Map
    // to store character and its frequency.
    for (int i = 0; i < input.length(); i++) {
        Integer count = map.get(input.charAt(i)); // if not in map
        if (count == null)
            map.put(input.charAt(i), 1);
        else
            map.put(input.charAt(i), count + 1);
    }
    System.out.println(map);
}

Output:

{G=2, C=1, Y=3, Z=4}

Thank you for your answer is there a way taht I can convert this to acm.jar package — relaxon, Apr 30 '13 at 09:30

find the number of every letters in a word

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