Convert tuple to list and back

Question

I'm currently working on a map editor for a game in pygame, using tile maps. The level is built up out of blocks in the following structure (though much larger):

level1 = (
         (1,1,1,1,1,1)
         (1,0,0,0,0,1)
         (1,0,0,0,0,1)
         (1,0,0,0,0,1)
         (1,0,0,0,0,1)
         (1,1,1,1,1,1))

where "1" is a block that's a wall and "0" is a block that's empty air.

The following code is basically the one handling the change of block type:

clicked = pygame.mouse.get_pressed()
if clicked[0] == 1:
    currLevel[((mousey+cameraY)/60)][((mousex+cameraX)/60)] = 1

But since the level is stored in a tuple, I'm unable to change the values of the different blocks. How do I go about changing the different values in the level in an easy manner?

don't use a tuple, just use a list from the beginning. It might really slow down your code if your level is huge, if you have to keep converting them — jamylak, Apr 30 '13 at 09:36
how about going with lists instead of tuples from the very beginning? — Krzysztof Bujniewicz, Apr 30 '13 at 09:37
@user2133308 btw just a compatibility note, you should use integer division `//` instead of just `/` because in Python 3, `/` will perform floating point division and screw up your code. — jamylak, Apr 30 '13 at 09:57

score 376 · Answer 1 · answered May 06 '14 at 14:27

376

Convert tuple to list:

>>> t = ('my', 'name', 'is', 'mr', 'tuple')
>>> t
('my', 'name', 'is', 'mr', 'tuple')
>>> list(t)
['my', 'name', 'is', 'mr', 'tuple']

Convert list to tuple:

>>> l = ['my', 'name', 'is', 'mr', 'list']
>>> l
['my', 'name', 'is', 'mr', 'list']
>>> tuple(l)
('my', 'name', 'is', 'mr', 'list')

answered May 06 '14 at 14:27

Khonix

4,128
1
16
15

10

This is not working for me. If I run the code in the first block to convert the tuple t to a list by passing t to list(), I get an error message: "*** Error in argument: '(t)'" This seems to happen to me only while debugging. Still confused. – Jimmy Aug 28 '18 at 19:30
15

@Jimmy that's because list is a debugger command, run `p list(...)` instead. – moritz Jan 24 '19 at 02:26

pradyunsg · Answer 2 · 2014-10-19T15:17:22.863

You have a tuple of tuples.
To convert every tuple to a list:

[list(i) for i in level] # list of lists

--- OR ---

map(list, level)

And after you are done editing, just convert them back:

tuple(tuple(i) for i in edited) # tuple of tuples

--- OR --- (Thanks @jamylak)

tuple(itertools.imap(tuple, edited))

You can also use a numpy array:

>>> a = numpy.array(level1)
>>> a
array([[1, 1, 1, 1, 1, 1],
       [1, 0, 0, 0, 0, 1],
       [1, 0, 0, 0, 0, 1],
       [1, 0, 0, 0, 0, 1],
       [1, 0, 0, 0, 0, 1],
       [1, 1, 1, 1, 1, 1]])

For manipulating:

if clicked[0] == 1:
    x = (mousey + cameraY) // 60 # For readability
    y = (mousex + cameraX) // 60 # For readability
    a[x][y] = 1

NumPy is the fundamental package for scientific computing with Python. NumPy's main object is the homogeneous multidimensional array. It is a table of elements (usually numbers), all of the same type, indexed by a tuple of positive integers. — pradyunsg, Dec 04 '16 at 03:25

score 27 · Answer 3 · answered Apr 30 '13 at 09:37

27

You can have a list of lists. Convert your tuple of tuples to a list of lists using:

level1 = [list(row) for row in level1]

or

level1 = map(list, level1)

and modify them accordingly.

But a numpy array is cooler.

answered Apr 30 '13 at 09:37

eumiro

207,213
34
299
261

AXO · Answer 4 · 2020-07-31T12:58:20.773

Since Python 3.5 (PEP 448 -- Additional Unpacking Generalizations) one can use the following literal syntax to convert a tuple to a list:

>>> t = (1,2,3)
>>> lst = [*t]
>>> lst
[1, 2, 3]
>>> *lst,  # back to tuple
(1, 2, 3)

A list comprehension can be use to convert a tuple of tuples to a list of lists:

>>> level1 = (
...      (1,1,1,1,1,1),
...      (1,0,0,0,0,1),
...      (1,0,0,0,0,1),
...      (1,0,0,0,0,1),
...      (1,0,0,0,0,1),
...      (1,1,1,1,1,1))
>>> level1_list = [[*row] for row in level1]
>>> level1_list
[[1, 1, 1, 1, 1, 1], 
 [1, 0, 0, 0, 0, 1], 
 [1, 0, 0, 0, 0, 1], 
 [1, 0, 0, 0, 0, 1], 
 [1, 0, 0, 0, 0, 1], 
 [1, 1, 1, 1, 1, 1]]
>>> *((*row,) for row in level1_list),
((1, 1, 1, 1, 1, 1), 
 (1, 0, 0, 0, 0, 1), 
 (1, 0, 0, 0, 0, 1), 
 (1, 0, 0, 0, 0, 1), 
 (1, 0, 0, 0, 0, 1), 
 (1, 1, 1, 1, 1, 1))
>>> _ == level1
True

score 20 · Answer 5 · answered Jun 20 '15 at 02:20

To convert tuples to list

(Commas were missing between the tuples in the given question, it was added to prevent error message)

Method 1:

level1 = (
     (1,1,1,1,1,1),
     (1,0,0,0,0,1),
     (1,0,0,0,0,1),
     (1,0,0,0,0,1),
     (1,0,0,0,0,1),
     (1,1,1,1,1,1))

level1 = [list(row) for row in level1]

print(level1)

Method 2:

level1 = map(list,level1)

print(list(level1))

Method 1 took --- 0.0019991397857666016 seconds ---

Method 2 took --- 0.0010001659393310547 seconds ---

score 16 · Answer 6 · answered May 30 '15 at 17:22

Why don't you try converting its type from a tuple to a list and vice versa.

level1 = (
     (1,1,1,1,1,1)
     (1,0,0,0,0,1)
     (1,0,0,0,0,1)
     (1,0,0,0,0,1)
     (1,0,0,0,0,1)
     (1,1,1,1,1,1))

print(level1)

level1 = list(level1)

print(level1)

level1 = tuple(level1)

print(level1)

tanzil · Answer 7 · 2013-04-30T10:16:56.530

5

Both the answers are good, but a little advice:

Tuples are immutable, which implies that they cannot be changed. So if you need to manipulate data, it is better to store data in a list, it will reduce unnecessary overhead.

In your case extract the data to a list, as shown by eumiro, and after modifying create a similar tuple of similar structure as answer given by Schoolboy.

Also as suggested using numpy array is a better option

edited Apr 30 '13 at 10:16

answered Apr 30 '13 at 09:51

tanzil

1,461
2
12
17

You should also write in this answer, that `numpy` will provide the fastest solution to working with this type of data. – jamylak Apr 30 '13 at 09:59
Of course you can use immutable data structures such as tuples even when you are manipulating data. The whole premise of functional programming and all that largely builds on persistence of data. But of course, in Python land you may want to go with the masses and mutate freely... – mike3996 Aug 26 '14 at 12:26

score 5 · Answer 8 · edited Dec 21 '18 at 23:42

5

List to Tuple and back can be done as below

import ast, sys
input_str = sys.stdin.read()
input_tuple = ast.literal_eval(input_str)

l = list(input_tuple)
l.append('Python')
#print(l)
tuple_2 = tuple(l)

# Make sure to name the final tuple 'tuple_2'
print(tuple_2)

edited Dec 21 '18 at 23:42

CDspace

2,639
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answered Dec 21 '18 at 18:44

Vijay Rangarajan

51
1
1

score 2 · Answer 9 · answered Apr 30 '13 at 10:02

You could dramatically speed up your stuff if you used just one list instead of a list of lists. This is possible of course only if all your inner lists are of the same size (which is true in your example, so I just assume this).

WIDTH = 6
level1 = [ 1,1,1,1,1,1,
           1,0,0,0,0,1,
           1,0,0,0,0,1,
           1,0,0,0,0,1,
           1,0,0,0,0,1,
           1,1,1,1,1,1 ]
print level1[x + y*WIDTH]  # print value at (x,y)

And you could be even faster if you used a bitfield instead of a list:

WIDTH = 8  # better align your width to bytes, eases things later
level1 = 0xFC84848484FC  # bit field representation of the level
print "1" if level1 & mask(x, y) else "0"  # print bit at (x, y)
level1 |= mask(x, y)  # set bit at (x, y)
level1 &= ~mask(x, y)  # clear bit at (x, y)

with

def mask(x, y):
  return 1 << (WIDTH-x + y*WIDTH)

But that's working only if your fields just contain 0 or 1 of course. If you need more values, you'd have to combine several bits which would make the issue much more complicated.

score 2 · Answer 10 · answered Feb 05 '21 at 15:24

Just using the command list did not work for me.

if you have a tuple just iterate until you have the elements there are necessary and after that append to a list. And if you go to the element level you can change it easily.

input:

level1 = (
         (1,1,1,1,1,1),
         (1,0,0,0,0,1),
         (1,0,0,0,0,1),
         (1,0,0,0,0,1),
         (1,0,0,0,0,1),
         (1,1,1,1,1,1))

level1_as_list=[]
for i in level1:
    inside_list=[]
    for j in i:
        inside_list.append(j)
    level1_as_list.append(inside_list)

print(level1_as_list)enter code here

output:

[[1, 1, 1, 1, 1, 1], [1, 0, 0, 0, 0, 1], [1, 0, 0, 0, 0, 1], [1, 0, 0, 0, 0, 1], [1, 0, 0, 0, 0, 1], [1, 1, 1, 1, 1, 1]]

DanielBell99 · Answer 11 · 2022-10-26T12:33:33.607

1

In my case, I wanted to merge rows/ lists:

a = ['Tom', 'Dick', 'Harry']
b = ['20', '32', '14']
c = ['foo', 'bar', 'blah']

lines = [list(row) for row in zip(a, b, c)]

lines = [['Tom', '20', 'foo'], ...]

edited Oct 26 '22 at 12:33

answered Oct 26 '22 at 12:19

DanielBell99

896
5
25
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Convert tuple to list and back

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