I'm trying to write a script that takes one string argument, divides the string into characters and uses the characters to create directory.
Ex: "./addUser asd" should create a directory named "a" inside the directory that the script is located, it also has to create a directory named "s" as a child directory of "a". Similarly, a directory named "d" has to be created inside the directory "s".
I'm stuck, can you please help?
Thanks in advance.
The easiest way that comes to mind is use a regex to insert / between each pair or characters with mkdir -p, like:
mkdir -p $(echo abc | perl -pi -e 's!.(?=.)!$&/!g')
or with sed:
mkdir -p $(echo abc | sed -e 's!.!&/!g')
From https://stackoverflow.com/a/7579016/2313067, you can use something like
x=$1
i=0
while [ $i -lt ${#x} ]; do mkdir ${x:$i:1}; cd ${x:$i:1}; i=$((i+1));done
One possible solution with mkdir -p:
echo asd | sed 's:.:&/:g' | xargs -n1 -I % mkdir -p "%"
or as usual eliminating the useless echo :) and the script format
#/bin/bash
<<< "$1" sed 's:.:&/:g' | xargs -n1 -I % mkdir -p "%"
this can be used as
< filename sed 's:.:&/:g' | xargs -n1 -I % mkdir -p "%"
the names are in the file filename
or
mkdir -p $(echo asd | sed 's:.:&/:g')
or
mkdir -p $(sed 's:.:&/:g' <<< "asd")
as usually, spaces and some special chars could make troubles...
I answered something similar to this a few days ago:
manupulating a string to create directories in unix
It boils down to
mkdir -p $(echo $1 | sed 's/[0-9a-zA-Z]/\0\//g')
or something similar
Use a while loop on your input.
#!/bin/bash
INPUT="$1"
while read -n 1 CHAR
mkdir "$CHAR"
cd "$CHAR"
done <<<"$INPUT"
