How to add an integer number and a float number in a bash shell script

Question

I have two numbers:

value1=686
value2=228.35

I am not able to add an integer and a float. Please help me out to get the result.

I am running it in bash.

possible duplicate of [How can I add numbers in a bash script](http://stackoverflow.com/questions/6348902/how-can-i-add-numbers-in-a-bash-script) — Karoly Horvath, May 03 '13 at 09:16
Korn shell 93 supports floating point. Do you have ksh installed? — cdarke, May 03 '13 at 10:02

score 24 · Accepted Answer · answered May 03 '13 at 09:19

24

echo 1 + 3.5 | bc

awk "BEGIN {print 1+3.5; exit}"

python -c "print 1+3.5"

perl -e "print 1+3.5"

Just replace the numbers with your variables, eg: echo $n1 + $n2 | bc

answered May 03 '13 at 09:19

Karoly Horvath

2

thnx :) bc language is not present on my linux machine and i dont have rights to install it asd well that was big problem. – sasuke May 03 '13 at 09:55

Konstantin Yovkov · Answer 2 · 2013-05-03T10:00:38.873

10

If you have the bc language installed, you can do the following:

#!bin/bash
numone=1.234
numtwo=0.124
total=`echo $numone + $numtwo | bc`
echo $total

If you don't have bc, then you can try with awk. Just in one single line:

echo 1.234 2.345 | awk '{print $1 + $2}'

There are plenty of other options, also. Like python, perl, php....

edited May 03 '13 at 10:00

answered May 03 '13 at 09:17

Konstantin Yovkov

`bc` is a language, so it may not be installed by default. try `sudo apt-get install bc` – Konstantin Yovkov May 03 '13 at 09:25
I dont have rights to install bc language, can we do it some other way. – sasuke May 03 '13 at 09:47
echo 1.234 2.345 | awk '{print $1 + $2}' – Konstantin Yovkov May 03 '13 at 09:53

score 5 · Answer 3 · edited Mar 28 '17 at 09:17

5

Bash doesn't have floating-point types, but you can use a calculator such as bc:

a=686
b=228.35
c=`echo $a + $b | bc`
echo "$c"

edited Mar 28 '17 at 09:17

Toby Speight

answered Mar 27 '17 at 15:23

tapas dey

score -7 · Answer 4 · edited May 03 '13 at 09:22

-7

 #!/bin/Bash
echo "Enter the two numbers to be added:"
read n1
read n2
answer=$(($n1+$n2))
echo $answer

edited May 03 '13 at 09:22

fedorqui

answered May 03 '13 at 09:14

snehal

2

686+228.35: syntax error: invalid arithmetic operator (error token is ".35") – sasuke May 03 '13 at 09:17
1

you can also add using... calc 686.0+228.35 – snehal May 03 '13 at 09:20
1

This doesn't work because the bash builtin math operator `$(( ))` only supports integers math operations. – Leon S. Mar 04 '21 at 08:19

4 Answers4