Getting the index of the value passed in

Question

public static int getIndex(String value, Constants type) {
    int myPosition = -1;
    for (int i = 0; i < type.length; i++) {
        if (type[i] == value) {
            myPosition = i;
            break;
        }
    }
    return myPosition;
}

I was thinking of a generic method where i pass the value and Constants into the method to get the required index of the string value. Its pretty much easy to do in JS, but i am not sure how can i toss a method of same in java.

CommonMethods.Utils.getIndex("Kevin", Contants.Name);

The above method is not working, as it says "length cannot be resolved or is not a field"

What is `Constants`? An enum? An interface? A class? The attribute `length` is valid on arrays (and when `length` is explicitly declared on a class or interface). — rgettman, May 08 '13 at 22:52
possible duplicate of [How do I compare strings in Java?](http://stackoverflow.com/questions/513832/how-do-i-compare-strings-in-java) — jlordo, May 08 '13 at 22:53

score 3 · Answer 1 · answered May 08 '13 at 22:55

3

Your Constants object should be some sort of Collection. Look those up. There's a lot of them with different attributes.

What you seem to be rewriting here is a ArrayList. Those already have a function to search inside called indexOf.

answered May 08 '13 at 22:55

Zan Lynx

53,022
10
79
131

How do i get the index of my object which is actually mapped to my Array... lets take my array contains three objects ["sas","asas","asas"]. ArrayList.indexOf(myObject) would return me the index of the Array items or index of the List. – Kevin May 08 '13 at 23:14

score 1 · Answer 2 · answered May 08 '13 at 22:52

1

type is a Constants, not an array. You can't run type.length because Constants does not define a length property.

If Constants is an enum you can use Constants.values() to get an array of all constants.

answered May 08 '13 at 22:52

wchargin

15,589
12
71
110

Getting the index of the value passed in

2 Answers2