I know you can compare chars in Java with normal operators, for example anysinglechar == y
. However, I have a problem with this particular code:
do{
System.out.print("Would you like to do this again? Y/N\n");
looper = inputter.getChar();
System.out.print(looper);
if(looper != 'Y' || looper != 'y' || looper != 'N' || looper != 'n')
System.out.print("No valid input. Please try again.\n");
}while(looper != 'Y' || looper != 'y' || looper != 'N' || looper != 'n');
The problem should not be the other method, inputter.getChar(), but I'll dump it anyway:
private static BufferedReader read = new BufferedReader(new InputStreamReader(System.in));
public static char getChar() throws IOException{
int buf= read.read();
char chr = (char) buf;
while(!Character.isLetter(chr)){
buf= read.read();
chr = (char) buf;
}
return chr;
}
The output I'm getting is as follows:
Would you like to do this again? Y/N
N
NNo valid input. Please try again.
Would you like to do this again? Y/N
n
nNo valid input. Please try again.
Would you like to do this again? Y/N
As you can see, the char I put in is an n
. It is then printed out correctly(hence it is to be seen twice). However, the comparison doesn't seem to become true.
I'm sure I'm overlooking something obvious.