Gruntfile getting error codes from programs serially

Question

I want to create a grunt file that runs 3 grunt tasks serially one after another regardless of whether they fail or pass. If one of the grunts task fails, I want to return the last error code.

I tried:

grunt.task.run('task1', 'task2', 'task3');

with the --force option when running.

The problem with this is that when --force is specified it returns errorcode 0 regardless of errors.

Thanks

score 7 · Accepted Answer · answered May 13 '13 at 20:06

Use grunt.util.spawn: http://gruntjs.com/api/grunt.util#grunt.util.spawn

grunt.registerTask('serial', function() {
  var done = this.async();
  var tasks = {'task1': 0, 'task2': 0, 'task3': 0};
  grunt.util.async.forEachSeries(Object.keys(tasks), function(task, next) {
    grunt.util.spawn({
      grunt: true,  // use grunt to spawn
      args: [task], // spawn this task
      opts: { stdio: 'inherit' }, // print to the same stdout
    }, function(err, result, code) {
      tasks[task] = code;
      next();
    });
  }, function() {
    // Do something with tasks now that each
    // contains their respective error code
    done();
  });
});

You have an extra comma after `opts: {stdio: 'inherit'}` but beautiful thanks a lot!!! — GTDev, Jun 04 '13 at 15:03
It's there on purpose ;) Trailing commas are cool in node >= 0.8. At least I think so heh — Kyle Robinson Young, Jun 04 '13 at 18:37

Gruntfile getting error codes from programs serially

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