float[][] pesIAlcada = {
{ 2.4f, 3.1f, 3.07f, 3.7f, 2.7f, 2.9f, 3.2f, 3f, 3.6f, 3.1f },
{ 19f, 18.7f, 22f, 24f, 17f, 18.5f, 21f, 20f, 18.7f, 22f, 18f },
{ 47f, 48f, 49f, 50f, 51f, 52f, 51.5f, 50.5f, 49.5f, 49.1f, 50f },
{ 101f, 104f, 106f, 107f, 107.5f, 108f, 109f, 110f, 112f, 103f } };
/*
* I already created an array. And I want to make a new one but some
* infomation from the old array. How can I do, plz?
*/
float[][] pesNeixement = new float[ROWS][COLS];
for (int i = 0; i < 2; i++) {
for (int j = 0; j < pesIAlcada[i].length; j++) {
System.out.print(pesIAlcada[i][j]);
}
}
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johnchen902
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Muna Lisa
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I suggest you avoid using `float` not only does it make examples like this more complicated, but it has much less precision (it is one billion times less accurate) – Peter Lawrey May 12 '13 at 10:52
4 Answers
1
Use this function to deep-copy a 2d array.
public static float[][] deepCopy(float[][] original, Integer offset, Integer numberOfRows) {
if (original == null) {
return null;
}
if (offset == null) {
offset = 0;
};
if (numberOfRows == null) {
numberOfRows = original.length;
};
final float[][] result = new float[numberOfRows - offset][];
for (int i = offset; i < numberOfRows; i++) {
result[i] = Arrays.copyOf(original[i], original[i].length);
}
return result;
}
And in your code:
float[][] pesNeixement = deepCopy(pesIAlcada, 0, 2);

flavian
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I want to make a new Array called pesNeixement and take just these two rows for the new array(pesNeixement) .. { {2.4f, 3.1f, 3.07f, 3.7f, 2.7f, 2.9f, 3.2f, 3f, 3.6f, 3.1f}, {19f, 18.7f, 22f, 24f,17f, 18.5f, 21f, 20f, 18.7f, 22f, 18f}, – Muna Lisa May 12 '13 at 10:28
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You might want to add an extra `offset` argument, in case someone wants to copy *x* rows starting at row *y*. – gkalpak May 12 '13 at 10:46
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@alex23 the code is identical to this : http://stackoverflow.com/a/1564856/951448 And this answer is 3 years older than the question you're referring to ... – Mr.Me May 12 '13 at 10:50
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0
It depends by your definition of "some information". If you want to copy a section of the array to a new one, then you can use System.arraycopy.
Example
int[] numbers = {4,5,6,7,8};
int[] newNumbers = new int[10];
System.arraycopy(numbers,0,newNumbers,0,3);

christopher
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I want to make a new Array called pesNeixement and take just these two rows for the new array(pesNeixement) .. { {2.4f, 3.1f, 3.07f, 3.7f, 2.7f, 2.9f, 3.2f, 3f, 3.6f, 3.1f}, {19f, 18.7f, 22f, 24f,17f, 18.5f, 21f, 20f, 18.7f, 22f, 18f}, – Muna Lisa May 12 '13 at 10:31
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So apply some reasoning, look at the answers you've been given and work out how you might get the top two lines. – christopher May 12 '13 at 10:32
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Yes, i did here float[][] pesNeixement = new float[ROWS][COLS]; for (int i = 0; i < 2; i++) { for (int j = 0; j < pesIAlcada[i].length; j++) { System.out.print(pesIAlcada[i][j]); } } The problem is that how can i change the name from pesIAlcada to pesNeixement ?? – Muna Lisa May 12 '13 at 10:36
0
If you want to copy some rows from pesIAlcada
in an new array (pesNeixement
) you can use something like this:
int fromRow = 0; // Start copying at row0 (1st row)
int toRow = 2; // Copy until row2 (3rd row) <- not included
// This will copy rows 0 and 1 (first two rows)
float[][] pesNeixement = new float[toRow - fromRow][];
for (int i = fromRow; i < toRow; i++) {
pesNeixement[i] = new float[pesIAlcada[i].length];
System.arraycopy(pesIAlcada[i], 0, pesNeixement[i], 0, pesIAlcada[i].length);
}
Also see this short demo.

gkalpak
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0
System.arrayCopy()
is the efficient way of creating new array from an existing array. What you can do with your own coding can be done using this also. Just explore

K Adithyan
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