Difference between java and C# doubles

Question

double is a type that represents 64-bit IEEE 754 floating-point number in Java

double is a type that represents 64-bit double-precision number in IEEE 754 format in C#.

Both languages follow the same specification. So why there is difference in following code? I checked Mono as well.

Double.MIN_VALUE == (Double.MIN_VALUE + 1.0); // false

Console.WriteLine(Double.MinValue == (Double.MinValue + 1.0)); // true

I suggest you read what these constants return. While some research was done, the documentation wasn't checked, which is a required step for a good question. — Security Hound, May 13 '13 at 16:42

Denys Séguret · Accepted Answer · 2013-05-13T16:15:51.590

5

Java's Double.MIN_VALUE is 2^-1074

while

C#'s Double.MinValue is -1.7976931348623157E+308

They have different values because they follow a different semantic.

A constant holding the smallest positive nonzero value of type double

Represents the smallest possible value of a Double [...] The value of this constant is negative 1.7976931348623157E+308

edited May 13 '13 at 16:15

answered May 13 '13 at 16:10

Denys Séguret

score 4 · Answer 2 · answered May 13 '13 at 16:11

4

C#'s Double.MinValue : The value of this constant is negative 1.7976931348623157E+308.

Java's Double.MIN_VALUE: A constant holding the smallest positive nonzero value of type double, 2-1074.

answered May 13 '13 at 16:11

AllTooSir

2 Answers2