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I am trying to simulate a mouse click on a QMenu item from a QMenuBar, for example clicking on "Save As" QAction using the QTestLib framework.

I am triyng this under Windows XP 32 bit and Qt 5.0.2.

Any Ideas?

Popovici Silviu
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2 Answers2

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Probably this question is not relevant for question owner, but I suppose it could be helpful for others.

Unlike QToolBar, QMenu doesn't have method widgetForAction. I found a simple workaround for this case. Try popup menu with QTest::mouseClick if nothing happens try to use QTest::keyClick(..., first_char_in_menu_tite, Qt::AltModifier). To simulate action execution you can navigate with Qt::Key_Down to action until you reach it and then press Qt::Key_Enter. I suppose following code can help you to understand

QMenu *menu = getMenu(mainWindow, menuName);
if (menu != nullptr) {
    QTest::keyClick(mainWindow, menu->title().at(1).toLatin1(), Qt::AltModifier);
}


QList<QAction *> actions = menu->actions();
foreach (QAction *action, actions) {
    if (action->objectName() == actionName) {
        QTest::keyClick(menu, Qt::Key_Enter);
        break;
    }
    QTest::qWait(1000);
    QTest::keyClick(menu, Qt::Key_Down);
}
ujohnny
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  • I made a similar example but for QComboBox here. Thanks for posting the QMenu one! https://gist.github.com/peteristhegreat/cbd8eaa0e565d0b82dbfb5c7fdc61c8d – phyatt Aug 18 '17 at 16:09
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You should use the QTest::mouseClick function. It will simulate the click on any QWidget. I have found that trying to click on a QMenu that causes a blocking call will not work with a unit test.

Keith
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    Not a good answer because the issue is being able to simulate a click specifically on one element, "Save As...", of a menu. Even if you can simulate a click on the "File" menu button, then the menu is displayed, somewhere in the menu rectangle is the "Save As..." part but how do you simulate a click on that? There is no child widget to access (or is there?). – user405 Apr 15 '14 at 22:17
  • This answer is wrong. Because the question ask for a mouseClick on a QAction. But QAction does not inherits from QWidget. Thus this solution is totally false. – LAL Mar 13 '17 at 20:08